Answer: see proof below
<u>Step-by-step explanation:</u>
Given: A + B + C = π and cos A = cos B · cos C
scratchwork:
A + B + C = π
A = π - (B + C)
cos A = cos [π - (B + C)] Apply cos
= - cos (B + C) Simplify
= -(cos B · cos C - sin B · sin C) Sum Identity
= sin B · sin C - cos B · cos C Simplify
cos B · cos C = sin B · sin C - cos B · cos C Substitution
2cos B · cos C = sin B · sin C Addition
Division
2 = tan B · tan C

<u>Proof LHS → RHS</u>
Given: A + B + C = π
Subtraction: A = π - (B + C)
Apply tan: tan A = tan(π - (B + C))
Simplify: = - tan (B + C)

Substitution: = -(tan B + tan C)/(1 - 2)
Simplify: = -(tan B + tan C)/-1
= tan B + tan C
LHS = RHS: tan B + tan C = tan B + tan C 
Slope = (change in 'y') / (change in 'x')
If you find two points where the line goes through the corners of boxes,
then count up the 'y' boxes and the 'x' boxes between those two points,
you'll find that the line rises 3 y-boxes for each x-box.
The slope of the line is 3 .
The answer you're looking for will be,
ANSWER: 64.
Steps:
To get this answer, follow the PEMDAS order of operations.
PEMDAS: Parenthesis, Exponents, Multiply, Divide, Add, Subtract.
(IN ORDER IF POSSIBLE)
I hoped this helped, you're welcome :)