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2 years ago

A line passes through the point (-2,6) and has a slope of 5/2 write an equation in slope-intercept form for this line

Mathematics

1 answer:

aalyn [17]2 years ago

4 0

Answer:

y=5/2x+11

Step-by-step explanation:

write part of equation and apply

6=5/2(-2)+n

n=11

y=5/2x+11

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Simplify the quotient 4.5 x 10^3/9 x 10^7 . Write your answer in scientific notation. Show your work.

astra-53 [7]

4.5*10^3/9*10^7=4.5/9*10^3*10^7=0.5*10^3*10^7. a^b*a^c=a^(b+c), so 10^3*10^7=10^(3+7)=10^10. 0.5*10^10=5*10^9, since we want to write in scientific notation where the leading number is bigger than one and smaller than 10.

8 0

3 years ago

5a+5-3a=13 i needed to make it 20 charatcers

defon

Answer:

5a plus 5 minus 3a is equal 13

Step-by-step explanation:

7 0

3 years ago

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the area of a rectangular land is 88 square metre & perimeter is 38 metre. what is the length & breadth of the land?

valentinak56 [21]

Answer:

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Step-by-step explanation:

5 0

3 years ago

let X represent the amount of time till the next student will arriv ein the library partking lot at the university. If we know t

AlekseyPX

Answer:

0.606531 = 60.6531% probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot.

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \mu e^{-\mu x}$

In which $\mu = \frac{1}{m}$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\mu x}$

The probability of finding a value higher than x is:

$P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}$

Mean of 4 minutes

This means that $m = 4, \mu = \frac{1}{4} = 0.25$

Find the probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot:

This is:

$P(2 \leq X \leq 132) = P(X \leq 132) - P(X \leq 2)$

In which

$P(X \leq 132) = 1 - e^{-0.25*132} = 1$

$P(X \leq 2) = 1 - e^{-0.25*2} = 0.393469$

$P(2 \leq X \leq 132) = P(X \leq 132) - P(X \leq 2) = 1 - 0.393469 = 0.606531$

0.606531 = 60.6531% probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot.

4 0

3 years ago

Will mark brainliest

Angelina_Jolie [31]

Answer:

K (-1,-1)

Step-by-step explanation:

4 0

2 years ago