Answer:
PT and SQ
Step-by-step explanation:
IF two segments are perpendicular then they will create 90 degree angles
segment PR and segment SQ cross over each other and create 90 degree angles therefore segment PR is perpendicular to segment SQ
(cos Ф -cos Ф)² + (cos Ф + cos Ф)²
Firstly: (cos Ф -cos Ф)² = 0² = 0
Secondly :(cos Ф + cos Ф)² = (2cos Ф)². = 4. (cos Ф)² = 4cos² Ф
Mind you when you raise a cosine (or sin or tan...) to the n power, the n power should affect the cosine only and NOT the angle Ф
Answer:
The model on the top right.
Answer:
294.5 m²
Step-by-step explanation:
shaded region = area of major sector + area of triangle
central angle of major sector = 360° - 130° = 230°
area of sector = area of circle × fraction of circle
A = π × 11.1² × 
= 
≈ 247.3 m²
area of triangle = 0.5 × 11.1 × 11.1 × sin130° ≈ 47.2 m²
shaded area = 247.3 + 47.2 ≈ 294.5 m²
