Answer:
5(F+13)=125 F=12
Step-by-step explanation:
Answer:
14.3 km
Step-by-step explanation:
Using the paths shown, we would need to add the path length from Belmont to Yardley and Yardley to Oxford. When we add 8.5 and 5.8, we get 14.3 km.
Hence,
the distance from Belmont to Oxford is 14.3 km.
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Answer:
n=3 then open bracket
Step-by-step explanation:
3n-(2+n)
=3x4-(2+4)
=12-6
=6
Answer:
81/250
Step-by-step explanation:
You would change it to a fraction.