Answer:
The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.
Step-by-step explanation:
Statement is incorrect. Correct form is presented below:
<em>The height </em>
<em> of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 90 feet per second is given by equation </em>
<em>, where </em>
<em> is time in seconds. After how many seconds will the ball be 84 feet above the ground. </em>
We equalize the kinematic formula to 84 feet and solve the resulting second-order polynomial by Quadratic Formula to determine the instants associated with such height:

(1)
By Quadratic Formula:

,
The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.
Answer:
2x-3
Step-by-step explanation:
f(x) = 3x-1
g(x) = x+2
Find (f-g)(x), this means we need to subtract g from x.
(3x-1) - (x+2)
Subtract the like terms:
3x -x = 2x
-1 -2 = -3
Combine them to get 2x-3
For multiplication, if both integers have like signs, it is always positive. If they have unlike signs it is negative.
For division, if both integers have like signs it is positive. If they have unlike signs it is negative.
Answer
A. 23
step-by-step explanation

We put x=3 into the function g


Also,

we substitute the value of g(3) into f



7.855 mm maybe the answer unless rounded to the tenths place to be 7.9 mm.