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2 years ago

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Kevin buys a bag of cookies that contains 8 chocolate chip cookies, 9 peanut butter cookies, 5 sugar cookies and 4 oatmeal cooki

es. What is the probability that Kevin randomly selects a chocolate chip cookie from the bag, eats it, then randomly selects an oatmeal cookie

1 answer:

IrinaVladis [17]2 years ago

5 0

Answer:

4/13 or 30.769%

Step-by-step explanation:

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A company dyes two sizes of rugs. A small rug requires 2 hours for dyeing and a medium-size rug requires 3 hours for dyeing. The

TiliK225 [7]

X + y > = 15.....this is saying that small rugs (x) + medium rugs (y) when made, are greater then or equal to 15...because they have to make at least 15

and since small rugs take 2 hrs......2x....and medium rugs take 3 hrs....3y...and they have to be made in less then 60 hrs...
2x + 3y < 60 <=== ur answer

7 0

3 years ago

The Department of Transportation would like to test the hypothesis that the average age of cars on the road is less than 12 year

puteri [66]

Answer:

$z=\frac{10.6-12}{\frac{4.1}{\sqrt{45}}}=-2.29$

Step-by-step explanation:

information given

$\bar X=10.6$ represent the sample mean

$\sigma=4.1$ represent the population standard deviation

$n=45$ sample size

$\mu_o =12$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

z would represent the statistic

$p_v$ represent the p value for the test

Hypothesis to test

We want to test if the true mean is less than 12, the system of hypothesis would be:

Null hypothesis: $\mu \geq 10$

Alternative hypothesis: $\mu < 10$

The statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

Replacing the info given we got:

We can replace in formula (1) the info given like this:

$z=\frac{10.6-12}{\frac{4.1}{\sqrt{45}}}=-2.29$

8 0

3 years ago

When my mother buys washing powder she pays R45,65 for a 3kg bag hkw much does she pay for 1kg

V125BC [204]

To solve this divide 4565 by 3.

7 0

3 years ago

Read 2 more answers

Which of these choices show a pair of equivalent expressions?

hoa [83]

Answer:

C AND D

Step-by-step explanation:

AP EX Confirmed

7 0

1 year ago

What are the minimum, first quartile, median, third quartile, and maximum of the data set? 2, 13, 17, 14, 9, 3, 16, 12

Alex777 [14]

So before anything, rearrange the data so that it's in ascending order: {2,3,9,12,13,14,16,17}

Next, the minimum and maximum are as they seem: the smallest and largest numbers in the data. Looking at our data, <u>2 is our minimum and 17 is our maximum.</u>

Next, to find the median, find the number that is in the middle of the data set. If there isn't one number in the middle, find the average of the two middle numbers to get your median:

$\{2,3,9,\overbrace{\boxed{12,13,}}^{\textsf{middle numbers}}14,16,17\}\\\\\frac{12+13}{2}\\\\\frac{25}{2}\\\\12.5$

<u>The median is 12.5.</u>

Next, to find the first quartile, or the lower quartile, find the "median" of the numbers to the left of the median.

$\overbrace{\{2,\boxed{3,9,}12,}^{\textsf{left of median}}13,14,16,17\}\\\\\frac{3+9}{2}\\\\\frac{12}{2}\\\\6$

<u>The first quartile is 6.</u>

Next, to find the third quartile, or the upper quartile, find the "median" of the numbers to the right of the median.

$\{2,3,9,12,\overbrace{13,\boxed{14,16,}17\}}^{\textsf{right of median}}\\\\\frac{14+16}{2}\\\\\frac{30}{2}\\\\15$

<u>The third quartile is 15.</u>

3 0

3 years ago