Let’s say it takes time t hours for the interception.
In that time the carrier travels 28t nm west and the helicopter 130t nm.
Now we use the sine rule to find the angle x which lies between the distance 175 and 130t.
sin(x)/28t=sin35/130t. So sin(x)=28sin35/130=14sin35/65=0.1235 and x=7.0964 degrees.
Therefore the helicopter should use a bearing of 35+7.0964=42.0964 degrees north of east or 47.9 degrees east of north approx.

8 0

3 years ago

How do you solve Jason ran 325 meters farther that Kim ran. Kim ran 4.2 kilometers how many meters did Jason run? Estimate to ch

labwork [276]

Change 4.2 kilometers to meters, which is 4200 meters, then add that to 325, so 4525 :)

5 0

4 years ago

Texas University Quarterback, Michael Daniels, is standing on his own 10-yard line. He throws a pass tword the opposite goal lin

dimulka [17.4K]

Answer: The function is $y=-\frac{28}{625}(x-35)^2+30$ .

Explanation:

It is given that Michael Daniels, is standing on his own 10-yard line. He throws a pass toward the opposite goal line. The football is 2 yards above the ground when the quarterback lets it go.

It follows a parabolic path. Reaching its highest point, 30 yards above the ground. It is caught 50 yards downfield at a point 2 yards above the ground.

So, the initial point is (10,2) and the other point is (60,2).

The height function of a football represents a downward parabola. The maximum point of the function is called vertex. So the vertex is (h,30).

The two point (10,2) and (60,2) have same y-coordinate, therefore the function is maximum at the midpoint of both points.

$midpoint=(\frac{10+60}{2}, \frac{2+2}{2})=(35,2)$