Question

And side q has a

Answer 1

Answer:

E

Step-by-step explanation:

Using the cosine and sine ratios in the right triangle and the exact values

cos60° = $\frac{1}{2}$ , sin60° = $\frac{\sqrt{3} }{2}$ , then

cos60° = $\frac{adjacent}{hypotenuse}$ = $\frac{s}{10}$ = $\frac{1}{2}$ ( cross- multiply )

2s = 10 ( divide both sides by 2 )

s = 5

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sin60° = $\frac{opposite}{hypotenuse}$ = $\frac{q}{10}$ = $\frac{\sqrt{3} }{2}$ ( cross- multiply )

2q = 10$\sqrt{3}$ ( divide both sides by 2 )

q = 5$\sqrt{3}$