If the probability of observing at least one car on a highway during any 20-minute time interval is 609/625, then the probability of observing at least one car during any 5-minute time interval is 609/2500
Given The probability of observing at least one car on a highway during any 20 minute time interval is 609/625.
We have to find the probability of observing at least one car during any 5 minute time interval.
Probability is the likeliness of happening an event among all the events possible. It is calculated as number/ total number. Its value lies between 0 and 1.
Probability during 20 minutes interval=609/625
Probability during 1 minute interval=609/625*20
=609/12500
Probability during 5 minute interval=(609/12500)*5
=609/2500
Hence the probability of observing at least one car during any 5 minute time interval is 609/2500.
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Answer:
Part a) Daniel's age is 2 years
Part b) Kevin's age is 8 years
Step-by-step explanation:
<u><em>The question is </em></u>
Part a) How old is Daniel?
Part b) How old is Kevin?
Let
x ----> Kevin's age
y ----> Daniel's age
we know that
-----> equation A
----> equation B
Equate equation A and equation B

solve for y



therefore
Daniel's age is 2 years
<em>Find the value of x</em>
substitute the value of y in any of the two equations


therefore
Kevin's age is 8 years
The diameter is twice as big as the radius
Set up two equations:
Greg = 330 + 75X
Heather = 660 + 45x
Set them to equal and solve for x:
330 + 75x = 660 + 45x
Subtract 330 from both sides:
75x = 330 + 45x
Subtract 45x from both sides:
30x = 330
Divide both sides by 30:
x = 330 / 30
X = 11
11 months they will have the same amount saved.
The ones that have the same number of rows and columns