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3 years ago

What is the answer to the question

Mathematics

1 answer:

Andre45 [30]3 years ago

7 0

Answer:

1/1

Step-by-step explanation:

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What is the explicit formula for this geometric sequence?

victus00 [196]

Answer:

The explicit formula for this geometric sequence is 27.3(n-1)

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3 years ago

The distance around a rectangular cafe is 35m . The ratio of length of the cafe to the width is 3:2. Find the dimension of the

marusya05 [52]

Hi there! :)

Answer:

Length = 10.5 m, width = 7 m.

Step-by-step explanation:

Given:

Perimeter, or P = 35 m

Ratio of l to w = 3 : 2

Since the ratio is 3 : 2, let l = 3x, and w = 2x.

We know that the formula for the perimeter of a rectangle is P = 2l + 2w. Therefore:

35 = 2(3x) + 2(2x)

35 = 6x + 4x

35 = 10x

x = 3.5

Plug this value of "x" into each expression to solve for the dimensions:

2(3.5) = w

w = 7 m

3(3.5) = l

l = 10.5 m

Therefore, the dimensions are:

Length = 10.5 m, width = 7 m.

4 0

3 years ago

What is the slope of a horizontal line?

Misha Larkins [42]

Answer:

Slope of a horizontal line. When two points have the same y-value, it means they lie on a horizontal line. The slope of such a line is 0, and you will also find this by using the slope formula.

8 0

3 years ago

Metallic silver has a density of 10.50. what is the mass, in g, of a silver ingot that is 28.0 cm long, 4.90 cm wide, and 3.60 c

frozen [14]

Answer:

5190 g

Step-by-step explanation:

Calculate the volume:

28.0 cm × 4.90 cm × 3.60 cm = 493.92 cm³

Density is mass divided by volume:

D = M / V

Solving for mass:

M = D V

Substituting values:

M = (10.50 g/cm³) (493.92 cm³)

M = 5186.16 g

Rounding to three significant figures, the mass is 5190 g.

3 0

3 years ago

The projected rate of increase in enrollment at a new branch of the UT-system is estimated by E ′ (t) = 12000(t + 9)−3/2 where E

nexus9112 [7]

Answer:

The projected enrollment is $\lim_{t \to \infty} E(t)=10,000$

Step-by-step explanation:

Consider the provided projected rate.

$E'(t) = 12000(t + 9)^{\frac{-3}{2}}$

Integrate the above function.

$E(t) =\int 12000(t + 9)^{\frac{-3}{2}}dt$

$E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+c$

The initial enrollment is 2000, that means at t=0 the value of E(t)=2000.

$2000=-\frac{24000}{\left(0+9\right)^{\frac{1}{2}}}+c$

$2000=-\frac{24000}{3}+c$

$2000=-8000+c$

$c=10,000$

Therefore, $E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000$

Now we need to find $\lim_{t \to \infty} E(t)$

$\lim_{t \to \infty} E(t)=-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000$

$\lim_{t \to \infty} E(t)=10,000$

Hence, the projected enrollment is $\lim_{t \to \infty} E(t)=10,000$

8 0

3 years ago