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pishuonlain [190]
3 years ago
9

What is the answer to the question

Mathematics
1 answer:
Andre45 [30]3 years ago
7 0

Answer:

1/1

Step-by-step explanation:

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Solve the absolute value equation 23 – 4 = 10. Use comma to separate the solutions, no spaces.
hichkok12 [17]

Answer: ?????

Step-by-step explanation: Is it doable? 23 - 4 = 19

8 0
3 years ago
Condense the following logs into a single log:
mamaluj [8]

QUESTION 1

The given logarithm is

8\log_g(x)+5\log_g(y)

We apply the power rule of logarithms; n\log_a(m)=\log_(m^n)

=\log_g(x^8)+\log_g(y^5)

We now apply the product rule of logarithm;

\log_a(m)+\log_a(n)=\log_a(mn)

=\log_g(x^8y^5)

QUESTION 2

The given logarithm is

8\log_5(x)+\frac{3}{4}\log_5(y)-5\log_5(z)

We apply the power rule of logarithm to get;

=\log_5(x^8)+\log_5(y^{\frac{3}{4}})-\log_5(z^5)

We apply the product to obtain;

=\log_5(x^8\times y^{\frac{3}{4}})-\log_5(z^5)

We apply the quotient rule; \log_a(m)-\log_a(n)=\log_a(\frac{m}{n} )

=\log_5(\frac{x^8\times y^{\frac{3}{4}}}{z^5})

=\log_5(\frac{x^8 \sqrt[4]{y^3} }{z^5})

7 0
3 years ago
DOES ANYONE KNOW THE ANSWER???
Greeley [361]
First one is the answer
7 0
3 years ago
In a store the number of dogs is 12 times greater than 3 times of cats. If there are 21 dogs in the store, how many cats are in
user100 [1]

Answer:

If you really meant that the number of dogs is 12 greater than 3 times the number of cats then:

3 cats

Step-by-step explanation:

21= number of dogs

c = number of cats

21 = 12 + (3c)

3c = 9

c = 3

8 0
3 years ago
HELP ASAP!!!!!!!!!!!!!!
yawa3891 [41]

Answer:

10

Step-by-step explanation:

just try to make the lines even and get the answer 10

7 0
3 years ago
Read 2 more answers
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