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uranmaximum [27]
2 years ago
13

Susan made $117 for hours 9 of work.

Mathematics
1 answer:
Irina18 [472]2 years ago
8 0
First we need to figure out how much Susan made per hour

117/9 = 13 dollars per hour

Then find out how much she makes in 7 hours

13 • 7 = 91 dollars

$91 in 7 hours
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Suppose you are finding 296 divided by 4 using partial quotients. Is 50 or 70 a more reasonable partial quotient? Explain.
Lyrx [107]
Round 296 up to 300 and then divide 300 by 4 mentally.  Answer:  75.  Which is a more reasonable partial quotient, 50 or 70?
8 0
3 years ago
X+y=0.5<br> x-y=1<br> elimination meathod
user100 [1]

Answer:

x=0.75, y=-0.25

Step-by-step explanation:

We can add the two equations to eliminate y and solve for x.

x+y+x-y=0.5+1

2x=1.5

x=0.75

Now, we can find for y by using substitution:

x+y=0.5 (given)

0.75+y=0.5

y=-0.25

Hope this helps :)

8 0
3 years ago
Segment wx is shown Explain how you would construct a perpendicular bisector of wx using a compass and a straightedge
n200080 [17]

Answer:

To perpendicular bisector of line segment WX. There are following steps:

1) Draw arcs or circles from points A and B on the both sides of WX.

2) Name the intersection points as W and X.

3) Use the straightedge to draw a line through points W and X.

4) Name the point as O

hence we have construct perpendicular bisector AB of WX which bisects at O.

4 0
3 years ago
a cow is tied to a pole fixed at the mid-point of a side of a square field of side 40m by means of a 14m long rope find the area
svp [43]

Step-by-step explanation:

The area that cow can graze is in the form of semicircle.

Radius of semicircle

Length of rope =14 m

Required area = 1/2 ×πr

=1/2×22/7×r^2

=1/2×22/7×14×14

=308m2

4 0
2 years ago
What is the perimeter of the triangle in units of the triangle formed by the points (-3,1), (-3,5), and (4,1)?
ira [324]

let's say

A(-3,1) B(-3,5) C(4,1)

we need to find the perimeter of ABC for that we find each of the sides

AB BC and AC

there is a formula to find the distance between 2 poins

let's say that a point has the structure A(x1,y1) where x=-3 and y=1 and B(x2,y2) where x2=-3 and y2=5

AB=\sqrt{(x2-x1)^2+(y2-y1)^2}

AB=\sqrt{(-3+3)^2+(5-1)^2}

AB=\sqrt{0^2+4^2}

AB=4

we do the same thing for AC and BC

AC=\sqrt{(4+3)^2+(1-1)^2}

AC=\sqrt{7^2+0^2}

AC=7

BC=\sqrt{(4+3)^2+(1-5)^2}

BC=\sqrt{7^2+(-4)^2}

BC=\sqrt{49+16}

BC=\sqrt{65}

The perimeter is equal to the sum of the sides

P=AB+AC+BC=4+7+\sqrt{65}=11+\sqrt{65}

8 0
2 years ago
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