Let's say you want to compute the probability

where

converges in distribution to

, and

follows a normal distribution. The normal approximation (without the continuity correction) basically involves choosing

such that its mean and variance are the same as those for

.
Example: If

is binomially distributed with

and

, then

has mean

and variance

. So you can approximate a probability in terms of

with a probability in terms of

:

where

follows the standard normal distribution.
Answer:
3 1/3 or 3.3(repeated)
Step-by-step explanation:
2/3 ÷ 1/5
= 2/3 × 5
= 10/3
= 3 1/3 or 3.3(repeated)
I hope this helped!
The height of this pyramid will be:
√(26^2 - (48/2)^2) = 10cm
So the volume is: V = 1/3 * 48^2 * 10 = 7680 cm^3
Answer:
16
Step-by-step explanation:
Add 13 both sides
That would give you 5v=80
Divide 80 by 5. So v would equal 16
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