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marin [14]
3 years ago
12

Alexis has 32 2/5 ounces of beads. How many necklaces can she make if each uses 2 7/10 ounces of beads?

Mathematics
2 answers:
love history [14]3 years ago
6 0
32 2/5 ÷ 2 7/10 let's turn above into improper fractions: 32 2/5 ----> 162/5 2 7/10 -----> 27/10 so, 162/5 ÷ 27/10 -------> 162/5 * 10/27 = 12 necklaces
melisa1 [442]3 years ago
3 0

Answer:

12 necklaces

Step-by-step explanation:

Given,

The total quantity of beads she has = 32\frac{2}{5} ounces,

Also, the quantity of beads needed for each necklace = 2\frac{7}{10} ounces,

Thus, the number of necklaces can be made

=\frac{\text{total quantity of beads}}{\text{quantity of beads needed for each necklace}}

=\frac{32\frac{2}{5}}{2\frac{7}{10}}

=\frac{162/5}{27/10}

=\frac{1620}{135}

=12

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What is the equation of the line that passes through the points (1,5) and (0,3)?
Pavlova-9 [17]

Answer:

y=2x+3

Step-by-step explanation:

first use the y2-y1/x2-x1 then use y=mx+b after

plug in 3 for y2 and 5 for y1

then plug in 0 for x2 and 1 for x1

\frac{3-5}{0-1}=\frac{-2}{-1} =2 and 2 is ur slope

___________________

now use y=mx+b

i usually use the first point but u can u anyone u want

plug in 1 for x

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and plug in 2 for m

5=2(1)+b

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3=b and b is ur y-intercept

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4 0
3 years ago
In a GP the second and fourth terms are 0.04 and I respectively find the common ratio and the first term​
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Answer:

common ratio=0.5, a1= 0.08

Step-by-step explanation:

r=a3/a2

r=a4/a3

compare both we get:

a3/a2=a4/a3

subtitute a2=0.04 and a4=1

a3/0.04=1/a3

(a3)^2=0.04*1

(a3)^2=0.04

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r=a2/a1

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4 0
3 years ago
Solve 9/10=z/8 . Round to the nearest tenth.
kompoz [17]
\boxed {Question}
\frac{9}{10} =  \frac{z}{8}

\boxed {Cross \  multiply}
10z = 8 \times 9

\boxed {Evaluate}
10z = 72
z = 72 \div 10
z = 7.2

\Longrightarrow \bf \ Answer \ : \ z = 7.2

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3 years ago
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