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Korolek [52]
2 years ago
14

15. Find m (6x + 1) (x + 4)

Mathematics
1 answer:
KiRa [710]2 years ago
4 0
62+25+4
i’m pretty sure that’s the answer, good luck
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Simplify to a single trig function with no denominator.<br>csc^2 x -cot^2 x
Murrr4er [49]

Convert everything to sine and cosine.

4 0
3 years ago
beau has 15 cans of beetlebots legs there are 8 legs in each can i found 7 more beetle bot legs how can we find the number of le
Natali5045456 [20]

Answer:

  multiply the number in each can by the number of cans and add the extras

Step-by-step explanation:

You can add them all up. This is the total of the number in each can and the extras:

  8 +8 +8 +8 +8 +8 +8 +8 +8 +8 +8 +8 +8 +8 +8 +7

Or you can take advantage of the invention of multiplication to simplify repeated addition. Multiply the number in each can by the number of cans, then add the extras.

  15×8 +7 = 127

3 0
3 years ago
A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 259.2-cm and a standard dev
Varvara68 [4.7K]

Answer:

The probability that the average length of rods in a randomly selected bundle of steel rods is greater than 259 cm is 0.65173.

Step-by-step explanation:

We are given that a company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 259.2 cm and a standard deviation of 2.1 cm. For shipment, 17 steel rods are bundled together.

Let \bar X = <u><em>the average length of rods in a randomly selected bundle of steel rods</em></u>

The z-score probability distribution for the sample mean is given by;

                            Z  =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \mu = population mean length of rods = 259.2 cm

           \sigma = standard deviaton = 2.1 cm

           n = sample of steel rods = 17

Now, the probability that the average length of rods in a randomly selected bundle of steel rods is greater than 259 cm is given by = P(\bar X > 259 cm)

 

     P(\bar X > 259 cm) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } > \frac{259-259.2}{\frac{2.1}{\sqrt{17} } } ) = P(Z > -0.39) = P(Z < 0.39)

                                                                = <u>0.65173</u>

The above probability is calculated by looking at the value of x = 0.39 in the z table which has an area of 0.65173.

8 0
3 years ago
Which of these triangle pairs can be mapped to each other using a single translation?
sergeinik [125]

Answer:- D shows the triangle pairs which can be mapped to each other using a single translation.


Explanation:-

Translation is a rigid transformation which creates a congruent image as that of the original figure such that the distance between the each point of the original figure and the image is fixed and same.

The translation mapping is given by (x,y)→(x+h,y+k) ,where h is the distance of the x coordinate of the each point of the original figure to the image and  k is the distance of the y coordinate of the each point of the original figure to the image.

In figure D we can see that the distance between each point of ΔCED is equal to the distance between each point of ΔMPN. Thus it shows  the triangle pairs which can be mapped to each other using a single translation.


4 0
3 years ago
Read 2 more answers
Marking people brainlist 7s-s=
Margaret [11]

Answer:

6s

Step-by-step explanation:

5 0
3 years ago
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