We have to choose the correct answer for the center of the circumscribed circle of a triangle. The center of the circumscribed circle of a triangle is where the perpendicular bisectors of a triangle intersects. In this case P1P2 and Q1Q2 are perpendicular bisectors of sides AB and BC, respectively and they intersect at point P. S is the point where the angle bisectors intersect ( it is the center of the inscribed circle ). Answer: <span>P.</span>
Answer:
0 = -54
Step-by-step explanation:
4(3x + 8) − 9 = 2(6x − 8) − 15
12x + 32 - 9 = 12x - 16 - 15
12x + 23 = 12x - 31
12x = 12x - 54
0 = -54
No solutions.
Best of Luck!
1/3 + 2/5 • 2/3
2 • 2 = 4
5 • 3 = 15
1/3 = 5/15
5/15 + 4/15 = 9/15 = 3/5
1/3 + 2/5 • 2/3 = 3/5
For 12, you would do 90=4x+42, and 48=4x, and x=12
for 15, you would do 90=8x+66, and 24=8x, and x=3
for 18, you would do 90=3x+57, and 33=3x, and x=11
Angle TRQ is 23 degrees and the length from S to R is 3.3 units.
I need help on this too
