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Archy [21]
3 years ago
14

What is the measure of angle R?

Mathematics
1 answer:
tigry1 [53]3 years ago
3 0

Option B:

25 degrees

Solution:

Given data in triangle PQR,

The side opposite to angle P is p.

The side opposite to angle Q is q.

The side opposite to angle R is r.

q = 36, r = 20, angle Q = 50°.

<u>To find the measure of angle R:</u>

Using law of sine,

$\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C}

$\Rightarrow\frac{p}{\sin P}=\frac{q}{\sin Q}=\frac{r}{\sin R}

Take only two sides.

$\Rightarrow\frac{q}{\sin Q}=\frac{r}{\sin R}

Substitute the given values.

$\Rightarrow\frac{36}{\sin 50^\circ}=\frac{20}{\sin R}

Do cross multiplication.

\Rightarrow36\times\sin R = \sin50^\circ\times20

sin 50° = 0.766

\Rightarrow36\times\sin R = 0.766\times20

\Rightarrow36\times\sin R = 15.32

$\Rightarrow\sin R = \frac{15.32}{36}

$\Rightarrow\sin R = 0.4255

$\Rightarrow R = \sin^{-1}(0.4255)

⇒ R = 25.18°

⇒ R = 25° (approximately)

Option B is the correct answer.

Hence the measure of angle R is 25 degrees.

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3 years ago
A survey of 76 commercial airline flights of under 2 hours resulted in a sample average late time for a flight of 2.55 minutes.
nika2105 [10]

Answer:

The best point of estimate for the true mean is:

\hat \mu = \bar X = 2.55

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2.55+1.96\frac{12}{\sqrt{76}}=5.248    

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Step-by-step explanation:

Information given

\bar X=2.55 represent the sample mean for the late time for a flight

\mu population mean

\sigma=12 represent the population deviation

n=76 represent the sample size  

Confidence interval

The best point of estimate for the true mean is:

\hat \mu = \bar X = 2.55

The confidence interval for the true mean is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

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Replacing we got:

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