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2 years ago

7

Describe what you see at the center of the liquid

Advanced Placement (AP)

2 answers:

morpeh [17]2 years ago

7 0

Answer:

where's the picture

can I have it?

Rina8888 [55]2 years ago

3 0

How are we supposed to answer this question without the picture or extra information???

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An architect makes a model of a new house. The model shows a tile patio in the backyard. In the model, each tile has length

STALIN [3.7K]

Answer:

$Ratio = \frac{1}{16}$ ----- Model length to Actual length

$Ratio = \frac{1}{256}$ ----- Model Area to Actual Area

Explanation:

Given

Model Measurement:

$Length = \frac{1}{2}\ in$

$Width = \frac{1}{6}\ in$

Actual Measurement:

$Length = \frac{2}{3}\ ft$

$Width = \frac{2}{9}\ ft$

Solving (a): Ratio of actual length to model length

Convert length from feet to inches

$Length = \frac{2}{3}\ ft$

$Length = \frac{2}{3}\ * 12in$

$Length = \frac{24\ in}{3}$

$Length = 8\ in$

The required ratio is calculated by dividing the model length by the actual length

$Ratio = \frac{Model}{Actual}$

$Ratio = \frac{1}{2}\ in/8\ in$

$Ratio = \frac{1}{2}/8$

$Ratio = \frac{1}{2} * \frac{1}{8}$

$Ratio = \frac{1}{16}$

Another possible way is to convert both measurement to a different unit:

Convert model length from inches to cm

$Length = \frac{1}{2}\ in$

$Model\ Length = \frac{1}{2} * 2.54cm$

$Model\ Length = \frac{1 * 2.54cm}{2}$

$Model\ Length = \frac{2.54cm}{2}$

$Model\ Length = 1.27 cm$

Convert actual length from ft to cm

$Length = \frac{2}{3}\ ft$

$Actual\ Length = \frac{2}{3} * 30.48cm$

$Actual\ Length = \frac{2 * 30.48cm}{3}$

$Actual\ Length = \frac{60.96cm}{3}$

$Actual\ Length = 20.32cm$

Then calculate the ratio as:

$Ratio = \frac{Model}{Actual}$

$Ratio = \frac{1.27cm}{20.32cm}$

$Ratio = \frac{1.27}{20.32}$

Simplify fraction

$Ratio = \frac{1.27/1.27}{20.32/1.27}$

$Ratio = \frac{1}{16}$

Solving (b): Model of Area;

Way 1:

In (a), we calculated the ratio of length to be:

$Ratio = \frac{1}{16}$

This is also the model of the width.

So, Ratio of Area is then calculated as:

$Ratio = \frac{1}{16}^2$

$Ratio = \frac{1}{256}$

Way (2): We calculate the actual area of the model and actual measurements.

Model Measurements

$Length = \frac{1}{2}\ in$

$Width = \frac{1}{6}\ in$

$Area = Length * Width$

$Area = \frac{1}{2} * \frac{1}{6} in^2$

$Area = \frac{1}{12}\ in^2$

Actual Measurements

$Length = \frac{2}{3}\ ft$

$Width = \frac{2}{9}\ ft$

$Area = Length * Width$

$Area = \frac{2}{3} * \frac{2}{9} ft^2$

$Area = \frac{4}{27} ft^2$

Convert to $in^2$

$Area = \frac{4}{27} * 144in^2$

$Area = \frac{4}{3} * 16in^2$

$Area = \frac{64}{3}in^2$

Ratio is then calculated as:

$Ratio = \frac{Model}{Actual}$

$Ratio = \frac{1}{12}/\frac{64}{3}$

$Ratio = \frac{1}{12} * \frac{3}{64}$

$Ratio = \frac{1}{4} * \frac{1}{64}$

$Ratio = \frac{1}{256}$

7 0

2 years ago

What is the enrollment period for a 529 college savings plan

blagie [28]

Answer:

year round

Explanation:

7 0

3 years ago

Read 2 more answers

Yo isn't election day tmro?

viktelen [127]

Yea bro crazy right lol

4 0

2 years ago

A worker is using a soft wire brush attached to an electric drill to clean a storage battery. What is wrong with this method? A.

MA_775_DIABLO [31]

Answer:

The correct answer is letter "B": The wire brush can remove too much material from the posts of the battery.

Explanation:

While cleaning a battery there are several considerations to be taken in order not to damage its function. At the moment of cleaning the posts, we must be very careful since this is the principal contact with the vehicle cables. In front of any damage, the vehicle may not even start.

Thus, using a soft wire brush with an electric drill is not appropriate since it could remove more material than the necessary from the posts.

4 0

3 years ago

Sayid grew up in Syria and often heard gunfire and explosions near his home, which caused him alarm and anxiety. He moved to the

Lady_Fox [76]

Answer: Mexico

Explanation:

5 0

3 years ago