Answer:
--- Radius
--- Height
Explanation:
Given
Object: Can (Cylinder)
Required
Maximize the volume
The surface area is:
Substitute 517.8 for S.A
Divide through by 2
Factorize:
Divide through by 
Make h the subject
--- (1)
Volume (V) is calculated as:
Substitute (1) for h
Open Bracket
Differentiate V
Set V' to 0
Collect Like Terms
Divide through by 3
Divide through by 
Take square root of both sides
Recall that:
Substitute 5.24 for r
Hence, the dimension that maximize the volume is:
--- Radius
--- Height
Encoding Failure refers to the brain's occasional failure to create a memory link.
This question is not complete; here is the complete question:
A one-hectare pond is sampled in early September. The sample yields 1 small catfish as well as 17 benthic invertebrates that represent 10 species.
If the pond is resampled a year later, which of the following would best indicate that the pond had been adversely affected by adjacent development?
A. An uncommon species has become more numerous
B. An increase in low-tolerance species has occurred
C. A decrease in high-tolerance species has occurred
D. Phylogenetic diversity has occurred
E. The biodiversity of the pond has decreased
The answer to this question is E. The biodiversity of the pond has decreased
Explanation:
In ecology, an ecosystem can be affected by adjacent developments including human developments or even other ecosystems and this can lead to positive or negative consequences.
In this context, one example that shows the was an adverse effect is "The biodiversity of the pond has decreased" because the reduction in diversity represents a major thread for an ecosystem as this makes species more vulnerable to disappear. Also, this can be caused by factors such as pollution caused by human development or major predator of the adjacent ecosystem feeding on organisms in the main ecosystem. Besides this, in the first sample, there were multiple species and a reduction in the second sample shows the ecosystem was weakened.
Answer:
√1.45 = 1.2041594578792
Explanation:
Step 1:
Divide the number (1.45) by 2 to get the first guess for the square root .
Step 2:
Divide 1.45 by the previous result. d = 1.45/0.725 = 2.
Average this value (d) with that of step 1: (2 + 0.725)/2 = 1.3625
previous value = 0.725 - 1.3625 = 0.6375.
0.6375 > 0.001
Now we repeat the step
Step 3:
Divide 1.45 by the previous result. d = 1.45/1.3625 = 1.0642201835.
Average this value (d) with that of step 2: (1.0642201835 + 1.3625)/2 = 1.2133600918
Error = new guess - previous value = 1.3625 - 1.2133600918 = 0.1491399082.
0.1491399082 > 0.001.
Step 4:
Divide 1.45 by the previous result. d = 1.45/1.2133600918 = 1.1950285903.
Average this value (d) with that of step 3: (1.1950285903 + 1.2133600918)/2 = 1.2041943411 (new guess).
Error = new guess - previous value = 1.2133600918 - 1.2041943411 = 0.0091657507.
0.0091657507 > 0.001.
Step 5:
Divide 1.45 by the previous result. d = 1.45/1.2041943411 = 1.2041245757.
Average this value (d) with that of step 4: (1.2041245757 + 1.2041943411)/2 = 1.2041594584
- previous value = 1.2041943411 - 1.2041594584 = 0.0000348827.
0.0000348827 <= 0.001. accuracy, we stop the iterations and use 1.2041594584 as the square root.
