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3 years ago

13

310.11 divided by 2????

2 answers:

ElenaW [278]3 years ago

8 0

Answer:

155.055

Step-by-step explanation:

ipn [44]3 years ago

6 0

Answer:

155.055

Step-by-step explanation:

hope this helps

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A kilobyte is 210 bytes and a megabyte is 220 bytes. How many kilobytes are in a megabyte?

Dmitrij [34]

Answer:

Around 1.04. Exactly 1.047619048

Step-by-step explanation:

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8 0

3 years ago

A grocery store sells avocados for $1.25 each. The graph shows the cost for different numbers of avocados.

Aleksandr [31]

I don’t know if this is right or not so, sorry if it’s wrong ;-;

1,2,3,4,5 = independent

c=1.25a = neither

$1.25, $2.50, $3.75, $5.00, $6.25 = dependent

Number of avocados = independent

Cost of avocados = dependent

If this is right then I’ll put the explanation in the comments, again sorry if it isn’t.

5 0

3 years ago

100x+300y=1.200<br> (2/3x+10)/100=(y+20)/300

AlexFokin [52]

Answer:

x= -4.284 and y= 1.432

Step-by-step explanation:

5 0

3 years ago

A particle moving in a planar force field has a position vector x that satisfies x'=Ax. The 2×2 matrix A has eigenvalues 4 and 2

andrey2020 [161]

Answer:

The required position of the particle at time t is: $x(t)=\begin{bmatrix}-7.5e^{4t}+1.5e^{2t}\\2.5e^{4t}-1.5e^{2t}\end{bmatrix}$

Step-by-step explanation:

Consider the provided matrix.

$v_1=\begin{bmatrix}-3\\1 \end{bmatrix}$

$v_2=\begin{bmatrix}-1\\1 \end{bmatrix}$

$\lambda_1=4, \lambda_2=2$

The general solution of the equation $x'=Ax$

$x(t)=c_1v_1e^{\lambda_1t}+c_2v_2e^{\lambda_2t}$

Substitute the respective values we get:

$x(t)=c_1\begin{bmatrix}-3\\1 \end{bmatrix}e^{4t}+c_2\begin{bmatrix}-1\\1 \end{bmatrix}e^{2t}$

$x(t)=\begin{bmatrix}-3c_1e^{4t}-c_2e^{2t}\\c_1e^{4t}+c_2e^{2t} \end{bmatrix}$

Substitute initial condition $x(0)=\begin{bmatrix}-6\\1 \end{bmatrix}$

$\begin{bmatrix}-3c_1-c_2\\c_1+c_2 \end{bmatrix}=\begin{bmatrix}-6\\1 \end{bmatrix}$

Reduce matrix to reduced row echelon form.

$\begin{bmatrix} 1& 0 & \frac{5}{2}\\ 0& 1 & \frac{-3}{2}\end{bmatrix}$

Therefore, $c_1=2.5,c_2=1.5$

Thus, the general solution of the equation $x'=Ax$

$x(t)=2.5\begin{bmatrix}-3\\1\end{bmatrix}e^{4t}-1.5\begin{bmatrix}-1\\1 \end{bmatrix}e^{2t}$

$x(t)=\begin{bmatrix}-7.5e^{4t}+1.5e^{2t}\\2.5e^{4t}-1.5e^{2t}\end{bmatrix}$

The required position of the particle at time t is: $x(t)=\begin{bmatrix}-7.5e^{4t}+1.5e^{2t}\\2.5e^{4t}-1.5e^{2t}\end{bmatrix}$

6 0

3 years ago

If the measure of angle 3 is 80 degrees and the measurer of angle 6 is (2x)

spin [16.1K]

Answer:
X = 40
Explanation: (2x) = 80
80/2 = 40
X = 40 degrees

5 0

2 years ago