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Lesechka [4]
3 years ago
7

Solve the inequality -5/7 - 6/7z < -2/7

Mathematics
1 answer:
viktelen [127]3 years ago
3 0

-\cfrac{5}{7}-\cfrac{6}{7}z~~ < ~~-\cfrac{2}{7}\implies \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{7}}{-5-6z~~ < ~~-2} \\\\\\ \stackrel{\textit{dividing by a negative value}}{-6z~}~\cfrac{3}{-6}}\implies \boxed{z~>-\cfrac{1}{2}}

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1 4th plus 5 8th equals
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These two have different denominators, so you find the least common multiple. This problem goes to be 2/8+5/8, which equals 7/8。
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3 years ago
Please include an explanation so I know how to do this. Thanks!
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Hello there,


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5 0
3 years ago
Express answer in exact form.
bazaltina [42]
The answer is 5.13 in²

Step 1. Calculate the diameter of the circle (d).
Step 2. Calculate the radius of the circle (r).
Step 3. Calculate the area of the circle (A1).
Step 4. Calculate the area of the square (A2).
Step 5. Calculate the difference between two areas (A1 - A2) and divide it by 4 (because there are total 4 segments) to get <span>the area of one segment formed by a square with sides of 6" inscribed in a circle.
</span>
Step 1:
The diameter (d) of the circle is actually the diagonal (D) of the square inscribed in the circle. The diagonal (D) of the square with side a is:
D = a√2            (ratio of 1:1:√2 means side a : side a : diagonal D = 1 : 1 : √2)
If a = 6 in, then D = 6√2 in.
d = D = 6√2 in

Step 2.
The radius (r) of the circle is half of its diameter (d):
r = d/2 = 6√2 / 2 = 3√2 in

Step 3.
The area of the circle (A1) is:
A = π * r²
A = 3.14 * (3√2)² = 3.14 * 3² * (√2)² = 3.14 * 9 * 2 = 56.52 in²

Step 4.
The area of the square (A2) is:
A2 = a²
A2 = 6² = 36 in²

Step 5:
(A1 - A2)/4 = (56.52 - 36)/4 = 20.52/4 =  5.13 in²
6 0
3 years ago
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Answer:

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