We develop an equation for the given situation by first writing the general equation for lines,
y = mx + b
Substituting to this given the values given above,
(1990) 430 = b
(2000) 400 = m(10) + 430
The value of m from the equation in 2000 is -3. Thus, the equation of that relates the variables is,
y = -3x + 430
Answer:
12.5
Step-by-step explanation:
30-60-90 triangles always have the height be sqrt3 the base.
Answer:
x = 2/3 or x = -2/3
Step-by-step explanation:
Solve for x over the real numbers:
9 x^2 = 4
Hint: | Divide both sides by a constant to simplify the equation.
Divide both sides by 9:
x^2 = 4/9
Hint: | Eliminate the exponent on the left-hand side.
Take the square root of both sides:
Answer:x = 2/3 or x = -2/3
Answer:
To multiply decimals, first multiply as if there is no decimal. Next, count the number of digits after the decimal in each factor. Finally, put the same number of digits behind the decimal in the product.
Step-by-step explanation:
Im not sure if its supposed y = -2x + 1 or y = 2x + 1 but I'll solve the problem for both.
First for y = -2x + 1
Since the line has to be parallel to y = -2x + 1
the slopes would be the same.
so, so far the equation would be
y = -2x + b
now we substitute (5,2) into the equation
2 = -2(5) + b
2 = -10 + b (Add 10 to both sides of the equation)
+10 +10
12 = b
Now that we solved for b
The equation would be
y = -2x + 12
^^ This equation is parallel to y = -2x + 1
Now to solve for an equation parallel to y = 2x + 1
Both equations would have the same slope
So far we would have
y = 2x + b
Now we solve for be by substituting the point (5,2)
2 = 2(5) + b
2 = 10 + b (subtract 10 from both sides)
-10 -10
-8 = b
After solving for b
The equation is
y = 2x - 8
This equation is parallel to y = 2x + 1
