<h2>A. $123.51</h2><h2 />
: $24.48 per year + price * 0.85
: $36.83 per year + price * 0.75
Substitute each value into both equations as price.
A:
129.4635
129.4625
B:
98.158
101.84
C:
145.2055
143.3625
D:
155.703
152.615
A is the lowest value where the second value is lower than the first.
Answer:
$27.00
Step-by-step explanation:
First, 10% of 30 = 3.
Second, 30 - 3 = 27
Hope this helps!
9514 1404 393
Answer:
FH = 16
Step-by-step explanation:
ΔGHE is a 5-12-13 triangle.
ΔEHF is a 3-4-5 triangle with a scale factor of 4, so side FH is 4·4 = 16 units.
_____
(3, 4, 5), (5, 12, 13), (7, 24, 25), (8, 15, 17) are all commonly used Pythagorean triples. The first two on the list are used in these triangles.
If you like, you can work out the numbers using the Pythagorean theorem, which tells you the square of the hypotenuse is equal to the sum of the squares of the other two sides.
For ΔEHG, that is ...
GE² = EH² + HG²
13² = EH² + 5²
EH² = 13² -5² = 169 -25 = 144
And for ΔEHF, ...
FE² = EH² +HF²
20² = 144 + HF²
400 -144 = HF² = 256
HF = √256 = 16
The length of side FH is 16 units.
Answer:
The answer is 21
Step-by-step explanation:
21x4+2=86
For this case we have a system of two equations with two variables:
Clear "o" from the first equation:
![8o = 382-12p\\o = \frac {382-12p} {8} = \frac {191-6p} {4}](https://tex.z-dn.net/?f=8o%20%3D%20382-12p%5C%5Co%20%3D%20%5Cfrac%20%7B382-12p%7D%20%7B8%7D%20%3D%20%5Cfrac%20%7B191-6p%7D%20%7B4%7D)
We substitute in the second equation:
![12 (\frac {191-6p} {4}) + 8p = 388\\3 (191-6p) + 8p = 388\\573-18p + 8p = 388\\-10p = 388-573\\-10p = -185\\p = \frac {185} {10}\\p = 18.5](https://tex.z-dn.net/?f=12%20%28%5Cfrac%20%7B191-6p%7D%20%7B4%7D%29%20%2B%208p%20%3D%20388%5C%5C3%20%28191-6p%29%20%2B%208p%20%3D%20388%5C%5C573-18p%20%2B%208p%20%3D%20388%5C%5C-10p%20%3D%20388-573%5C%5C-10p%20%3D%20-185%5C%5Cp%20%3D%20%5Cfrac%20%7B185%7D%20%7B10%7D%5C%5Cp%20%3D%2018.5)
ANswer:
![p = 18.5](https://tex.z-dn.net/?f=p%20%3D%2018.5)