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KATRIN_1 [288]
3 years ago
8

1 plus 1 equals something in a house! Can you answer??

Mathematics
1 answer:
Zarrin [17]3 years ago
3 0

Answer:

horse horse horse horse

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A company manufactirung snowboards has fixed costs of $200 per day and total cost of $3800 per day at a daily output of 20 board
polet [3.4K]
A. The cost per 20 boards is 3800. so each board costs 3800/20 or $190. So the cost equation is C(x) = 200 + 190x

B. Divide the cost function by x. C(x)/x = 200/x + 190

C. The graph will be a curve that starts at (1,390) and curves down and to the right. Your last point will be at (30, 200/30+190) Your asymptote will be the horizontal line at 190 because as x tends to infinity, the term 200/x goes to zero. (There is also a vertical asymptote at x = 0 because you can't divide by zero, but your graph won't include x=0)

D. The average cost tends to 190 which was your horizontal asymptote.
7 0
3 years ago
What are the zeros of f(x)=(x-2)(3x+1)​
Basile [38]

2,-  \frac{1}{3}

6 0
2 years ago
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Please help. If this isn't done by today i'm grounded :(
DedPeter [7]

Answer:

B. temporary

Step-by-step explanation:

The last sentence says that the alignment of atoms does not last long.

4 0
2 years ago
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12% of children are nearsighted, but this condition often is not detected until they go to kindergarten. A school district tests
Klio2033 [76]

Answer:

There is a 34.60% probability that 0 or 1 of them is nearsighted.

Step-by-step explanation:

For each children, there are only two possible outcomes. Either they are nearsighted, or they are not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem, we have that:

12% of children are nearsighted. This means that p = 0.12.

A school district tests all incoming kindergarteners' vision. In a class of 18 kindergarten students, what is the probability that 0 or 1 of them is nearsighted?

There are 18 students, so n = 18

This probability is:

P = P(X = 0) + P(X = 1)

So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{18,0}.(0.12)^{0}.(0.88)^{18} = 0.1002

P(X = 1) = C_{18,1}.(0.12)^{1}.(0.88)^{17} = 0.2458

So

P = P(X = 0) + P(X = 1) = 0.1002 + 0.2458 = 0.3460

There is a 34.60% probability that 0 or 1 of them is nearsighted.

5 0
3 years ago
?????????????this question
Eduardwww [97]

Answer:

answer: 17


Step-by-step explanation:


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3 years ago
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