Answer:
The approximate percentage of SAT scores that are less than 865 is 16%.
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
Approximately 68% of the measures are within 1 standard deviation of the mean.
Approximately 95% of the measures are within 2 standard deviations of the mean.
Approximately 99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean of 1060, standard deviation of 195.
Empirical Rule to estimate the approximate percentage of SAT scores that are less than 865.
865 = 1060 - 195
So 865 is one standard deviation below the mean.
Approximately 68% of the measures are within 1 standard deviation of the mean, so approximately 100 - 68 = 32% are more than 1 standard deviation from the mean. The normal distribution is symmetric, which means that approximately 32/2 = 16% are more than 1 standard deviation below the mean and approximately 16% are more than 1 standard deviation above the mean. So
The approximate percentage of SAT scores that are less than 865 is 16%.
Answer: The graph is shifted 2 units to the right.
Step-by-step explanation:
Given a function f(x), we know that one transformation rule is:
If 
then the function is shifted "k" units to the right.
Therefore, for the function 
, when we subtract 2 from the input, then we get the function g(x) in the form:
We can conclude that subtracting 2 from the input of the function , then the graph is shifted 2 units to the right.
Answer:
A, it will decrease by 90.
Step-by-step explanation:
If the number is 92,320 and you interchange 2 and 3, you would get 92,230. 320-230 equals 90, therefore giving you the answer.
Answer:
corporate team-building event cost will cost $98
Step-by-step explanation:
A corporate team-building event costs $32, plus an additional $1 per attendee.
Let cost be C
The expression for the above statement
C($)= 32+n(1)
Where n is the number of attendees
So a situation where there are 66 attendees, the total cost will be
C($) = 32 +66(1)
C($) = 32+66
C($)= 98
Children = .65 * people
people = 520 / .65
800 people were in attendance
