What are the zeros of the quadratic equation y=5(2x-1)(x+3)
2 answers:
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Answer:
Given: The transformation g(x) =6f(x) ......[1]
To find the corresponding values of g(x) for the given transformation.
At x = -7, f(x) = 8
then,
By substituting the value of f(x) = 8 in [1] we have
Similarly,
For x= -3 , f(x) = 3, then
By substituting the value of f(x) = 3 in [1] we have
For x= 0, f(x) = -1 , then
By substituting the value of f(x) = -1 in [1] we have
For x= 2, f(x) = 7, then
By substituting the value of f(x) = 7 in [1] we have
For x= 10, f(x) = 5, then
By substituting the value of f(x) = 5 in [1] we have
Therefore ; we have the corresponding values of g(x) as shown below;
x f(x) g(x)
-7 8 48
-3 3 18
0 -1 -6
2 7 42
10 5 30