What are the zeros of the quadratic equation y=5(2x-1)(x+3)
2 answers:
The answer is x = 1/2 or -3
Answer:
x = 1/2 or -3
Step-by-step explanation:
to find the zeros, we need to find the values of x which would cause y to become zero,
i.e solve x for :
5(2x-1)(x+3) = 0 (divide both sides by 5)
(2x-1)(x+3) = 0
hence either
2x-1 = 0 (add 1 to both sides)
2x = 1 (divide both sides by 2)
x = 1/2 --> first zero
or
x+3 = 0 (subtract 3 from both sides)
x = -3 ----> 2nd zero
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