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Step2247 [10]
3 years ago
8

Use the Distributive Property to simplify the following: 7(y + 3) =

Mathematics
1 answer:
Ksju [112]3 years ago
8 0

Answer:

7y+21

Step-by-step explanation: i solve it hope this help.

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HELPPPPPP ITS URGENT!!!!!!!!!!!!!!!!!
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Answer:

A

Step-by-step explanation:

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3 years ago
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What prime factorization 32 is between 1 and 10
olga55 [171]

Answer:

2 x 2 x 2 x 2 x 2, which can also be written 32 = 2⁵

Step-by-step explanation:

8 0
3 years ago
A positive number is 30 less than its square. Find the number.
Veronika [31]
<span><span>x = x^2 - 30

or

x^2 - x - 30 = 0
Factors to
(x-6)(x+5) = 0

x = +6 is the positive number</span></span>
8 0
4 years ago
Find the set of solutions for the linear system.
Illusion [34]

Answer:

The system has infinitely many solutions.

\left\begin{array}{ccc}x_1&=&-\frac{1}{3}x_2-\frac{16}{9}x_4-\frac{2}{9}  \\x_2&=&s_1\\x_3&=&-\frac{4}{3}x_4+\frac{1}{3}  \\x_4&=&s_2\end{array}\right

Step-by-step explanation:

To find the solution for this system of linear equations -3x_1-x_2+4x_3=2\\-3x_3 - 4x_4 = -1you must:

Step 1: Transform the augmented matrix to the reduced row echelon form.

A matrix is a rectangular arrangement of numbers into rows and columns.

A system of equations can be represented by an augmented matrix.

In an augmented matrix, each row represents one equation in the system and each column represents a variable or the constant terms.

This is matrix that represents the system

\left[ \begin{array}{ccccc} -3 & -1 & 4 & 0 & 2 \\\\ 0 & 0 & -3 & 4 & -1 \end{array} \right]

The augmented matrix can be transformed by a sequence of elementary row operations to the matrix.

There are three kinds of elementary matrix operations.

  1. Interchange two rows (or columns).
  2. Multiply each element in a row (or column) by a non-zero number.
  3. Multiply a row (or column) by a non-zero number and add the result to another row (or column).

Using elementary matrix operations, we get that

Row Operation 1: Multiply the 1st row by -1/3

Row Operation 2: Multiply the 2nd row by -1/3

Row Operation 3: Add 4/3 times the 2nd row to the 1st row

\left[ \begin{array}{ccccc} 1 & \frac{1}{3} & 0 & \frac{16}{9} & - \frac{2}{9} \\\\ 0 & 0 & 1 & \frac{4}{3} & \frac{1}{3} \end{array} \right]

Step 2: Interpret the reduced row echelon form

The reduced row echelon form of the augmented matrix is

\left[ \begin{array}{ccccc} 1 & \frac{1}{3} & 0 & \frac{16}{9} & - \frac{2}{9} \\\\ 0 & 0 & 1 & \frac{4}{3} & \frac{1}{3} \end{array} \right]

which corresponds to the system

x_1+\frac{1}{3}x_2+ \frac{16}{9}x_4=-\frac{2}{9} \\x_3+ \frac{4}{3}x_4=\frac{1}{3}

We see that the variables x_2, x_4 can take arbitrary numbers; they are called free variables. Let x_2=s_1, x_4=s_2. All solutions of the system are given by

\left\begin{array}{ccc}x_1&=&-\frac{1}{3}x_2-\frac{16}{9}x_4-\frac{2}{9}  \\x_2&=&s_1\\x_3&=&-\frac{4}{3}x_4+\frac{1}{3}  \\x_4&=&s_2\end{array}\right

The system has infinitely many solutions.

8 0
4 years ago
If QR is 7 less than twice X, RS is 61 less than 5 times x, and QS is 11 more than x, find X and the measure of each side.
poizon [28]

Answer:

We can't find the answer unless there's the total amount of circumstances.

Step-by-step explanation:

QR= 2x-7

RS= x-61

QS= x+11

2x+7+x-61+x+11

? = 4x-43

4 0
3 years ago
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