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tankabanditka [31]
3 years ago
5

Suppose you invest $16000 at 9% interest and that it is compounded daily. How much will you have in 8 years?

Mathematics
1 answer:
kramer3 years ago
4 0

Answer:

The amount after 8 years is $ 16,031.579

Step-by-step explanation:

Given as :

The Principal invested = $ 16000

The rate of interest compounded daily = 9 %

The time period = 8 years

Let The amount after 8 years = $ A

<u>From Compounded method </u>

Amount = Principal invested × (1+\dfrac{\textrm Rate}{365\times 100})^{365\times \textrm Time}

Or, Amount = 16000 × (1+\dfrac{\textrm 9}{365\times 100})^{365\times \textrm 8}

Or, Amount = 16000 × (1.0002465)^{8}

∴  Amount = $ 16,031.579

Hence The amount after 8 years is $ 16,031.579   Answer

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solve the system of equations by finding the reduced row-echelon form of the augmented matrix for the system of equations. x-2y+
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Answer:

x = -5, y = -6, z = -3

Step-by-step explanation:

Given the system of three equations:

\left\{\begin{array}{l}x-2y+3z=-2\\6x+2y+2z=-48\\x+4y+3z=-38\end{array}\right.

Write the augmented matrix for the system of equations

\left(\begin{array}{ccccc}1&-2&3&|&-2\\6&2&2&|&-48\\1&4&3&|&-38\end{array}\right)

Find the reduced row-echelon form of the augmented matrix for the system of equations:

\left(\begin{array}{ccccc}1&-2&3&|&-2\\6&2&2&|&-48\\1&4&3&|&-38\end{array}\right)\sim \left(\begin{array}{ccccc}1&-2&3&|&-2\\0&-14&16&|&36\\0&-6&0&|&36\end{array}\right)\sim \left(\begin{array}{ccccc}1&3&-2&|&-2\\0&16&-14&|&36\\0&0&-6&|&36\end{array}\right)

Thus, the system of three equations is

\left\{\begin{array}{r}x+3z-2y=-2\\16z-14y=36\\-6y=36\end{array}\right.

From the last equation:

y=-6

Substitute it into the second equation:

16z-14\cdot (-6)=36\\ \\16z=36-84\\ \\16z=-48\\ \\z=-3

Substitute y = -6 and z = -3 into the first equation:

x+3\cdot (-3)-2\cdot (-6)=-2\\ \\x=-2+9-12\\ \\x=-5

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Answer:

104m, 0.096km, 2100cm

Step-by-step explanation:

0.096 kilometres = 9600

2100 cm

104m = 10400 cm

10400, 9600, 2100

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Answered by Gauthmath

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