To me it looks like your right
Mabye try making the triangle a right triangle and use SohCahToa (sin, cos, tan) to figure out each angle?
Answer:
A) B is greater
B) when C = 21, A = 5 and B = 15
C) A must be 0, 5, or 12 for C to be greater than B
Step-by-step explanation:
A) when a = -3, c = -20 and b = 4(-3)-5 so B = -17
B) when c = 21, a = 5 and b = 4(5)-5 so B = 15
C) C is greater than B when a = 0, 5, and 12
when a = 0, b = 4(0)-5 or -5
when a = 5, b = 4(5)-5 or 15
when a = 12, b = 4(12)-5 or 43
Answer: a) BC = 1386.8 ft
b) CD = 565.8 ft
Step-by-step explanation:
Looking at the triangle,
AD = BD + 7600
BD = AD - 7600
Considering triangle BCD, we would apply the the tangent trigonometric ratio.
Tan θ = opposite side/adjacent side. Therefore,
Tan 24 = CD/BD = CD/(AD - 700)
0.445 = CD/(AD - 700)
CD = 0.445(AD - 700)
CD = 0.445AD - 311.5 - - - - - - - -1
Considering triangle ADC,
Tan 16 = CD/AD
CD = ADtan16 = 0.287AD
Substituting CD = 0.287AD into equation 1, it becomes
CD = 0.445AD - 311.5
0.287AD = 0.445AD - 311.5
0.445AD - 0.287AD = 311.5
0.158AD = 311.5
AD = 311.5/0.158
AD = 1971.52
CD = 0.287AD = 0.287 × 1971.52
CD = 565.8 ft
To determine BC, we would apply the Sine trigonometric ratio which is expressed as
Sin θ = opposite side/hypotenuse
Sin 24 = CD/BC
BC = CD/Sin24 = 565.8/0.408
BC = 1386.8 ft
Answer is d
it would be b^12
