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weeeeeb [17]
2 years ago
6

Please Help! it's simple!

Mathematics
1 answer:
ss7ja [257]2 years ago
8 0

Answer:

28.27

circumference of finding a circle divided by two.

(2\pi \:r {}^{2} ) \div 2

(2×3.14×9)/2

56.55/2

28.27

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A banner is hung for a party. The distance from a point on the bottom edge of the banner to the floor can be determined by using
GrogVix [38]

That's possible when function tends to zero

\\ \rm\hookrightarrow 0.25x^2-x+9.5=0

\\ \rm\hookrightarrow 1/4x^2-x+19/2=0

\\ \rm\hookrightarrow x^2-x+38=0

\\ \rm\hookrightarrow x=\dfrac{1\pm\sqrt{1-152}}{2}

\\ \rm\hookrightarrow x=\dfrac{1\pm\sqrt{151}i}{2}

8 0
2 years ago
Read 2 more answers
I would most likely appreciate it if you would help me.
prohojiy [21]

Answer: The answe would be 26.70

Step-by-step explanation:

15% of 178

convert: 0.15 x 178

=26.70

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8 0
3 years ago
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Please help asap with explanation !! <3 ​
77julia77 [94]

Answer:

Step-by-step explanation:

15/45 * 100

=33.33%

8 0
2 years ago
10. Given m and b, write the equation of the line:<br><br> m=-4; b=2
steposvetlana [31]

Answer:

y= -4x + 2

Step-by-step explanation:

Y= mx + b is used to find the equation of the line

m=-4 a d b= 2

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6 0
2 years ago
In a manufacturing plant that produces new computers, a 0.15 probability exists that a computer will be defective. if five compu
Sindrei [870]

The probability that all of them will be defective is 0.0000759375

<em><u>Explanation</u></em>

The general <u>Binomial Probability</u> formula is....

P= ^nC_{r}*p^r*(1-p)^n^-^r, where p is the probability of success, n is the total number of trials and r is the desired numbers of trials.

Given, the probability that a computer will be defective is 0.15 , so p = 0.15

Five computers are manufactured and we need to find the probability that all of them will be defective. That means, n = 5 and r = 5

Now according to the above formula....

P= ^5C_{5}*(0.15)^5*(1-0.15)^5^-^5 \\ \\ P= 1*(0.15)^5* (0.85)^0\\ \\ P=(0.15)^5 =0.0000759375

So, the probability that all of them will be defective is 0.0000759375

7 0
3 years ago
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