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katrin2010 [14]
4 years ago
7

What is the difference of the two polynomials? (7y2 + 6xy) – (–2xy + 3)

Mathematics
2 answers:
VARVARA [1.3K]4 years ago
6 0
 7y^{2} + 8xy-3 Answer B
Paraphin [41]4 years ago
4 0
<span>(7y2 + 6xy) – (–2xy + 3)

7y^2 + 6xy +2xy +3

7y^2 +8xy +3

8xy + 7y^2 +3</span>
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sasho [114]

The graph of the pH function can be created by plotting the output of

input values of the hydronium ions, <em>x</em>, in the range 0 < x ≤ 1.

Correct responses:

First part:

Please find attached the graph of the pH function

From the attached graph of the pH function, we have;

  • The point where the pH value is 0 is \underline{(1, \, 0)}}
  • The point where the pH value is 1  is \underline{(0.1, \, 1)}
  • The pH level if the hydronium ion is raised to 0.50 is approximately <u>0.3</u>

Second part

  • Please find attached the graph of the transformations, f(x) + 1, and f(x + 1) of the parent log function.

  • The transformation that results in a y-intercept is \underline{f(x, \, 1)}, because, at x = 0, f(x + 1) = 0.

<h3>Which method can be used to find the pH values using a graph?</h3>

First part

The pH function is; f(x) = -log₁₀x

Please find attached the graph of the pH function created with MS Excel

Where;

x = Amount of hydronium ions

f(x) = pH level

When the pH is 0, we have;

-log₁₀x = 0

Which gives;

x = 10⁰ = 1

  • When the pH value is 0, the point on the graph is \underline{(0, 1)}

When the pH value is 1, we have;

-log₁₀x = 1

log₁₀x = -1

x = 10⁻¹ = 0.1

  • The point on the graph where the pH value is 1 is \underline{(0.1, \, 1)}

  • From the graph, the ideal pH level if the amount of hydronium ions is raised to 0.50 is pH = 0.301029996 ≈ <u>0.30</u>

Second Part

The given transformations are;

f(x) + 1, and f(x + 1)

  • <u>The graph of the transformations created with MS Excel is attached</u>

At the y-intercept, x = 0

From the transformation, f(x) + 1, we have;

At x = 0, the transformation = -log₁₀(0) + 1

log₁₀(0) = Does not exist (DNE)

Therefore;

f(x) + 1 = -log₁₀(0) + 1 = DNE

The transformation, f(x + 1), at x = 0, gives;

f(0 + 1) = -log₁₀(0 + 1) = -log₁₀(1) = 0

Therefore;

The function f(x + 1) = -log₁₀(x + 1) is defined at x = 0, and therefore, has a y-intercept

  • The transformation that has a y-intercept is \underline{f(x + 1)}

Learn more about the pH values here:

brainly.com/question/3610155

4 0
3 years ago
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