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Alex17521 [72]
2 years ago
7

Francesca tried to evaluate an expression. Here is her work: 3(5)2–18÷3 = 3(25)–18÷3 = 75–18÷3 = 57÷3 = 19 Is Francesca's work c

orrect?
Mathematics
1 answer:
hram777 [196]2 years ago
5 0

Answer:

Nope. Moltiplication (and thus divisions) has to be done before any addition or subtractions, unless parenthesis indicate otherwise.

3(5)^2 - 18\div 3 = 3(25) - 6 = 75-6=69

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The volume of a right circular cone is found using the equation V = 1 3 π r 2 h . Which equation represents the volume solved fo
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Solving for a variable in an equation means, we are changing the subject of formula of the equation.

The equation of r is: \mathbf{r = \sqrt{\frac{3V}{\pi h}}}

The equation is given as:

\mathbf{V = \frac 13 \pi r^2h}

We start by multiplying both sides by 3

\mathbf{V \times 3= \frac 13 \pi r^2h \times 3}

Rewrite as:

\mathbf{3V= \pi r^2h}

Divide both sides by \mathbf{\pi h}

\mathbf{\frac{3V}{\pi h}= \frac{\pi r^2h}{\pi h}}

Cancel out common factors

\mathbf{\frac{3V}{\pi h}= r^2}

Take square roots of both sides

\mathbf{\sqrt{\frac{3V}{\pi h}}= \sqrt{r^2}}

Evaluate the right-hand sides

\mathbf{\sqrt{\frac{3V}{\pi h}}= r}

Make r the subject

\mathbf{r = \sqrt{\frac{3V}{\pi h}}}

Hence, the resulting equating for r is:

\mathbf{r = \sqrt{\frac{3V}{\pi h}}}

Read more about the subject of formulas at:

brainly.com/question/21866313

6 0
3 years ago
What would be the best method to use in order to solve the following quadratic equation? x²+14x+13=0
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Help me with this problem please:)
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Find The art length of a sector with an area of 8 square units.
frez [133]
\bf \textit{area of a sector of a circle}\\\\
A=\cfrac{\theta \pi r^2}{360}\quad 
\begin{cases}
r=radius\\
\theta =angle~in\\
\qquad degrees\\
------\\
A=8\\
r=4
\end{cases}\implies 8=\cfrac{\theta \pi 4^2}{360}\implies \cfrac{8\cdot 360}{4^2\pi }=\theta 
\\\\\\
\cfrac{2880}{16\pi }=\theta \implies \boxed{\cfrac{180}{\pi }=\theta }\\\\
-------------------------------\\\\

\bf \textit{arc's length}\\\\
s=\cfrac{\theta \pi r}{180}\quad 
\begin{cases}
r=radius\\
\theta =angle~in\\
\qquad degrees\\
------\\
\theta =\frac{180}{\pi }\\
r=4
\end{cases}\implies s=\cfrac{\frac{180}{\underline{\pi} }\underline{\pi} \cdot 4}{180}\implies s=\cfrac{\underline{180}\cdot 4}{\underline{180}}
\\\\\\
\boxed{s=4}

if you do a quick calculation on what that angle is, you'll notice that it is exactly 1 radian, and an angle of 1 radian, has an arc that is the same length as its radius.

that's pretty much what one-radian stands for, an angle, whose arc is the same length as its radius.
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