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Oduvanchick [21]
1 year ago
6

A veterinary technician recorded the weights of 12 puppies. Of these 12 puppies, 3 weighed over 6 pounds. What percentage of the

puppies weighed over 6 pounds?
A: 3

B: 9

C: 15

D: 25

Show your work!
Mathematics
1 answer:
OLga [1]1 year ago
3 0

The percentage value of puppies weighing over 6 pounds is 25%

What is Percentage?

Percentage is a relative number that represents the hundredth part of any quantity. One percent (symbolised 1%) is one hundredth part; consequently, 100 percent denotes the complete amount and 200 percent defines twice the supplied amount.

Solution:

Given that there are 12 puppies in total and 3 of them weighted above 6 pounds

To calculate the percentage we need to divide 3 by 12 and then multiply it by 100

= (3/12) * 100

= 25%

To learn more about <u>Percentage</u> from the given link

brainly.com/question/843074

#SPJ1

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A box is being created out of a 15 inch by 10 inch sheet of metal. Equal-sized squares are cutout of the corners, then the sides
ivolga24 [154]

Answer:

Therefore the dimensions of the square should be 0.1528 inch by 0.1528 inch so, the box  has largest volume.

Step-by-step explanation:

Given that,

A box is being created out of a 15 inches by 10 inches sheet of metal.

The length of the one side of the squares which are cut out of the each corners of the metal sheet be x.

The length of the metal box be = (15-2x) inches.

The width of the metal box be =(10-2x) inches

The height of the metal box be =x inches

Then, the volume of the metal box= length×width×height

                                                         =(15-2x)(10-2x)x cubic inches

                                                         =(150x-50x²+4x³) cubic inches

∴ V= 4x³-50x²+15x

Differentiating with respect to x

V'=12x²-100x+15

Again differentiating with respect to x

V''=24x-100

For maximum or minimum value, V'=0

12x²-100x+15=0

Apply quadratic formula x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}, here a=12, b= -100 and c=15

x=\frac{-(-100)\pm\sqrt{(-100)^2-4.12.15}}{2.12}

\Rightarrow x=\frac{100\pm\sqrt{9280}}{2.12}

\Rightarrow x=0.1528,8.18

For x= 8.18, The value of (15-2x) and (10-2x) will negative.

∴x=0.1528 .

Now, V''|_{x=0.1528}=24(0.1528)-100

∴At x=0.1528 inch, the volume of the metal box will be maximum.

Therefore the dimensions of the square should be 0.1528 inch by 0.1528 inch so, the box  has largest volume.

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3 years ago
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