A veterinary technician recorded the weights of 12 puppies. Of these 12 puppies, 3 weighed over 6 pounds. What percentage of the
1 answer:
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Answer:
3
Step-by-step explanation:
Given:
Team heights (inches):
61, 57, 63, 62, 60, 64, 60, 62, 63
To find: IQRs (interquartile ranges) of the heights for the team
Solution:
A quartile divides the number of terms in the data into four more or less equal parts that is quarters.
For a set of data, a number for which 25% of the data is less than that number is known as the first quartile
For a set of data, a number for which 75% of the data is less than that number is known as the third quartile
Terms in arranged in ascending order:
Number of terms = 9
As number of terms is odd, exclude the middle term that is 62.
is median of terms
Number of terms (n) = 4
Median =
So,
So, 25% of the heights of a team is less than 60 inches
is the median of terms
Median =
So,
So, 75% of the heights of a team is less than 63 inches
Interquartile range =
The interquartile range is a measure of variability on dividing a data set into quartiles.
The interquartile range is the range of the middle 50% of the terms in the data.
So, 3 is the range of the middle 50% of the heights of the students.
Answer:
The answer for A is .
The answer for B is <em>4 cans. </em>
The answer of C is <em>$98.</em>
Step-by-step explanation:
A-
Multiply 2.5 by 3.5 and you'll get 8.75 Multiply 3.5 by 1.2 and you'll get 4.2; divide and your answer will be 2.1 Add to 8.75 Get 10.85 Subtract from area of door ( 3m because 1.5 times 2 is 3) and you'll get 7.85
B-
Divide 7.85 by 2.5 and you'll get 3.104; round that and you'll get 4 cans.
C-
Multiply the amount of cans (4) by 24.5. Do this and you'll get $98.
Hope this was helpful!!!