Evaluate 5r - 8.35s when r = 12 and s = 4.
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Answer:
Step-by-step explanation:
The function that we have to study in this problem is
The domain of a function is defined as the set of all the possible values of x that the function can take.
For a square-root function, there are some limitations to the possible value of the argument in the root.
In particular, the argument of a square root must be equal or greater than zero, because the square root of a negative number is not defined.
Therefore, in this case, we have to set the following condition for the domain:
And by solving, we get
which means that the domain of this function is all real numbers equal or greater than 5.