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Novay_Z [31]
3 years ago
7

Evaluate 5r - 8.35s when r = 12 and s = 4.

Mathematics
2 answers:
Dvinal [7]3 years ago
6 0

Answer:

It should be 26.6

Step-by-step explanation:

wel3 years ago
4 0

Answer:

26.6

Step-by-step explanation:

5r=60

8.35s=33.4

60-33.4=26.6

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Help please I don't know what to do plz just send the answers because I'm tired and I cba to do calculations
Lyrx [107]
Answer is A
Just make sure you do know how to do them :)

4 0
3 years ago
Solve the following differential equation: (1− 5 y +x) dy/dx +y= 5/x −1 .<br><br> C=
Ganezh [65]

Answer:

y(1+x)+x-5\ln xy=C

Step-by-step explanation:

Consider the given differential equation is

(1-\frac{5}{y}+x)\frac{dy}{dx}+y=\frac{5}{x}-1

(1-\frac{5}{y}+x)\frac{dy}{dx}=\frac{5}{x}-1-y

(1-\frac{5}{y}+x)dy=(\frac{5}{x}-1-y)dx

Taking all variables on right sides.

(1-\frac{5}{y}+x)dy-(\frac{5}{x}-1-y)dx=0

(-\frac{5}{x}+1+y)dx+(1-\frac{5}{y}+x)dy=0

Let as assume,

M=-\frac{5}{x}+1+y and N=1-\frac{5}{y}+x

Find partial derivatives \frac{\partial M}{\partial y} and \frac{\partial N}{\partial x}

\frac{\partial M}{\partial y}=1 and \frac{\partial N}{\partial x}=1

Since \frac{\partial M}{\partial y}=\frac{\partial N}{\partial x}, therefore the given differential equation is exact.

The solution of the exact differential equation is

\int Mdx+\int N(\text{without x)}dy=C

\int (-\frac{5}{x}+1+y)dx+\int (1-\frac{5}{y})dy=C

yx-5\ln x+x+y-5\ln y=C

y+x+xy-5\ln x-5\ln y=C

y(1+x)+x-5(\ln x+\ln y)=C

y(1+x)+x-5\ln xy=C

7 0
3 years ago
An engineer is planning a new water pipe installation. The circular pipe has a diameter of d=20\text{ cm}d=20 cmd, equals, 20, s
aivan3 [116]

Answer: The answer is 314.28 cm² (approx.).


Step-by-step explanation:  Given that an engineer is going to install a new water pipe. The diameter of this circular pipe is, d = 20 cm.

We need to find the area 'A' of the circular cross-section of the pipe.

Given, diameter of the circular section is

\textup{d}=20~\textup{cm}.

So, the radius of the circular cross-section will be

\textup{r}=\dfrac{\textup{d}}{2}=\dfrac{20}{2}=10~\textup{cm}.

Therefore, cross-sectional area of the pipe is

\textup{A}=\pi \textup{r}^2=\dfrac{22}{7}(10)^2=\dfrac{2200}{7}=314\dfrac{2}{7}=314.28~.~.~.~\textup{cm}^2.

Thus, the answer is 314.28 cm² (approx.).

4 0
3 years ago
Solve |p + 2| = 10Solve |p + 2| = 10<br><br> {-12}<br> {-8, 8}<br> {-12, 8}
valentinak56 [21]

By definition, we have

|p+2| = \begin{cases} p+2 &\text{ if } p+2 \geq 0 \\-p-2 &\text{ if } p+2 < 0 \end{cases}

So, we have to solve two different equations, depending of the possible range for the variable. We have to remember about these ranges when we decide to accept or discard the solutions:

Suppose that p+2\geq 0 \iff p \geq -2

In this case, the absolute value doesn't do anything: the equation is

p+2 = 10 \iff p = 10-2 = 8

We are supposing p \geq -2, so we can accept this solution.

Now, suppose that p+2 < 0 \iff p < -2. Now the sign of the expression is flipped by the absolute value, and the equation becomes

-p-2 = 10 \iff -p = 12 \iff p = -12

Again, the solution is coherent with the assumption, so we can accept this value as well.

3 0
3 years ago
Plzzz help i am ineeeddeddeedeededed of it!!!
Vikentia [17]
Sallys statement is always true
for example:
-6 + 2 = -4
but if I turn it around
2 - 6 = -4
same answer

-6 -6 = -12
swap around -6 - 6 = 12
same answer

again -3 + 6 = 3
and 6 - 3 = 3
6 0
4 years ago
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