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3 years ago

5

So um anyone know how to do this?

1 answer:

Kitty [74]3 years ago

5 0

We need to find distance they travel as a function of time. This simply means that x is the function of time. The destination is 120 miles away, this is irrelevant for the question that is currently being asked. However, we know that they have already travelled 20 miles and are going 50 miles and hour. So lets plug in what we have.

50 is our rate of change, so we match that with the x.

20 is our constant, the distance already travelled.

This means our function is:

f(x) = 50x + 20

This means our answer is D) f(x) = 50x + 20

Lets also plug in 120 to solve how much further they need to travel before arriving.

120 is our f(x) as it is the final distance travelled.

120 = 50x + 20

120-20 = 50x

100 = 50x

100/50 = x

2 = x

This means that they need to travel 2 hours in addition to the 20 miles they have already gone.

I hope I've helped! :)

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3 years ago

Which equation represents a quadratic function?

Elena-2011 [213]

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3 years ago

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masya89 [10]

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3 years ago

Read 2 more answers

Determine the equation for the parabola graphed below

Elza [17]

Answer:

$y=(x-2)^2-1$

Step-by-step explanation:

The given function:

Since the function is open upwards means is of $y=x^2$

And we can see one unit down and 2 units shifted on right in parent function.

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3 years ago

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pychu [463]

The equation of a hyperbola is $x^{2}$ /9 - $y^{2}$ /4 = 1

What are the steps to Hyperbola equation ?

To find the equation of hyperbola, the following steps must be taken. You need to identify;

The coordinate of the center

The coordinate of the vertices

The coordinate of the foci

The general equation of a hyperbola can be expressed as

$x^{2}$ / $a^{2}$ - $y^{2}$ / $b^{2}$ = 1

From the graph, we have the following parameters

a = 3

$a^{2}$ = $3^{2}$ = 9

b = 2

$b^{2}$ = $2^{2}$ = 4

The equation of a hyperbola can be expressed as

$x^{2}$ /9 - $y^{2}$ /4 = 1

The vertices = V(+/-a,0) = (+/-3,0)

The center = C(0,0)

The focus = F(+/-C, 0)

Where $C^{2}$ = $a^{2}$ + $b^{2}$

C = $\sqrt{9 + 4}$

C = $\sqrt{13}$

Focus = F(+/- $\sqrt{13}$ , 0)

The general equation for asymptote = +/- b/a X

= +/-2/3X

Therefore, the equation of a hyperbola can be expressed as

$x^{2}$ /9 - $y^{2}$ /4 = 1

Learn more about hyperbola here: brainly.com/question/3405939

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2 years ago