Question

Can someone please help me

Answer 1

Answer:

Step-by-step explanation:

1) Statements                         Reasons

ABCD is a trapezoid               Given

AD ║ BC                                  bases of trapezoid are parallel

∠AED = ∠CEB                          vertically opposite angles are equal

∠EBC = ∠ADE          alternate interior angles are equal and BD is transversal                

∠ECB = ∠EAD          alternate interior angles are equal and AC is transversal

ΔAED ~ ΔCEB            ∠ECB = ∠EAD & ∠AED = ∠BEC & ∠EBC = ∠ADE

                                all angles are same and their shape is same, so similar

2) hope you can write 2nd one as above two column proof

T is the mid point of QR

U is the mid point of QS

V is the mid point of RS

Definition: The segment of line joining the middle points of two sides of a triangle is called middle segment.

Inference: A middle segment of a triangle is parallel to the third side and its lengths is half the third side's.

so here TU ║ RV and TU = RV  

UV ║ TR and UV = TR

so TUVR becomes a parallelogram

∠TUV = ∠TRV -------->  condition 1

same goes with parallelogram TQUV

∠TQU = ∠UVT ----------> condition 2

same goes with parallelogram TUSV

∠UTV = ∠USV ------------> condition 3

from the above 3 conditions we can say

ΔQRS ~ ΔVUT

3) see the below figure for graph

in both triangles ∠B is common

AC and TS are parallel lines

BC  and BA are transversals

∠C ∠S are equal --> corresponding angles

∠A ∠T are equal ---> corresponding angles

so ΔABC & ΔTBS are similar