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IgorLugansk [536]
3 years ago
15

the length of a rectangle is 4 less than 3 times its width.if its width is 5 cm what will be its perimeter​

Mathematics
2 answers:
Katyanochek1 [597]3 years ago
3 0

Answer:

32cm

Step-by-step explanation:

Alchen [17]3 years ago
3 0

Answer:

Given that: The length of a rectangle is 4 less than 3 times its width. The perimeter of a rectangle is 32 cm.

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Answer:

B. 2

Step-by-step explanation:

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A pack of folders has a length of 5 inches, a width of 12 inches, and a height of 1 inch. The pack of folders will be shipped in
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Answer:

A) Each pack of folders has a volume of 60 cubic inches.

B) The box has a volume of about 720 cubic inches

D) If the box help 20 packs of folders, it would have a volume of about 1,200 cubic inches.

Step-by-step explanation:

<em><u>Verify each statement</u></em>

<em>A) Each pack of folders has a volume of 60 cubic inches.</em>

The statement is True

Because

The volume of each pack of folders is equal to

V=(5)(12)(1)=60\ in^{3}

<em>B) The box has a volume of about 720 cubic inches</em>

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Because

The volume of the box is equal to the volume  of one pack of folders multiplied by 12

so

V=(12)60=720\ in^{3}

<em>C) If the box held 15 packs of folders, it would have a volume of about 1,200 cubic inches</em>

The statement is False

Because

Applying proportion

\frac{12}{720}\frac{packs}{in^{3}}=\frac{15}{x}\frac{packs}{in^{3}}\\ \\x=720*15/12\\ \\x=900\ in^{3}

900\ in^{3}\neq 1,200\ in^{3}

<em>D) If the box help 20 packs of folders, it would have a volume of about 1,200 cubic inches.</em>

The statement is True

Because

Applying proportion

\frac{12}{720}\frac{packs}{in^{3}}=\frac{20}{x}\frac{packs}{in^{3}}\\ \\x=720*20/12\\ \\x=1,200\ in^{3}

1,200\ in^{3}= 1,200\ in^{3}

<em>E) Each pack of folders has a volume of 24 cubic inches.</em>

The statement is False

Because

The volume of each pack of folders is equal to

V=(5)(12)(1)=60\ in^{3}

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3 years ago
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Answer:

y = 2x - 3/4

Step-by-step explanation:

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Making the indicated substitutions, we get

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