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3 years ago

Use the sum of cubes identity to write this polynomial expression in factored form: 8x3 + 27.

Mathematics

2 answers:

lorasvet [3.4K]3 years ago

8 0

The answer is 1989 because that’s how much I know

zvonat [6]3 years ago

3 0

Answer:

${8x}^{3} + 27 \\ = {8x}^{3} + {3}^{3} \\ let : 8x \: be \: a \\ : 3 \: be \: b \\ = > {a}^{3} + {b}^{3} : \\ {(a + b)}^{3} = (a + b)( {a}^{2} + 2ab + {b}^{2} ) \\ {(a + b)}^{3} = ( {a}^{3} + 3{a}^{2} b + 3a {b}^{2} + {b}^{3} ) \\ ( {a}^{3} + {b}^{3} ) = {(a + b)}^{3} - 3ab(a + b) \\ \therefore( {8x}^{3} + 27) = {(8x + 3)}^{3} - 72(8x + 3)$

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3 years ago

PLEASE HELP ME IlL MARK U BRAINLEST

pogonyaev

Using the concept of odd and even functions, it is found that the functions are classified as follows:

1. Even.

2. Odd.

3. Neither.

4. Odd.

<h3>What are odd and even function?</h3>

If f(x) = f(-x), the function is even.

If f(x) = -f(-x), the function is odd.

If none of the statements above are true, the function is neither.

For the square function, we have that:

f(x) = x².

f(-x) = (-x)² = x² = f(x).

Hence it is even. The square root function is defined only for non-negative values, hence it is neither odd nor even.

For the cube function, we have that:

f(x) = x³.

f(-x) = (-x)³ = -x³ = -f(x).

Hence it is odd, as is the cube root, as the cube root function is defined for all real values.

More can be learned about odd and even functions at brainly.com/question/24410059

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Fynjy0 [20]

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