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3 years ago

Use the sum of cubes identity to write this polynomial expression in factored form: 8x3 + 27.

Mathematics

2 answers:

lorasvet [3.4K]3 years ago

8 0

The answer is 1989 because that’s how much I know

zvonat [6]3 years ago

3 0

Answer:

${8x}^{3} + 27 \\ = {8x}^{3} + {3}^{3} \\ let : 8x \: be \: a \\ : 3 \: be \: b \\ = > {a}^{3} + {b}^{3} : \\ {(a + b)}^{3} = (a + b)( {a}^{2} + 2ab + {b}^{2} ) \\ {(a + b)}^{3} = ( {a}^{3} + 3{a}^{2} b + 3a {b}^{2} + {b}^{3} ) \\ ( {a}^{3} + {b}^{3} ) = {(a + b)}^{3} - 3ab(a + b) \\ \therefore( {8x}^{3} + 27) = {(8x + 3)}^{3} - 72(8x + 3)$

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3 years ago

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Mademuasel [1]

Answer:

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2 years ago

Two consecutive numbers have a sum of 346. What are the numbers?

seraphim [82]

Answer:

81,82,83

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3 years ago

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3 years ago

1) -24, -4, 16, 36, ...<br> Find a23

viktelen [127]

We're given the Arithmetic Progression <em>-24, -4, 16, 36 ...</em> .

We know that a term in an AP is generally represented as:

$\bf a_n\ =\ a\ +\ (n\ -\ 1)d$

where,

a = the first term in the sequence
n = the number of the term/number of terms
d = difference between two terms

We need to find $\sf a_2_3$ .

From the given progression, we have:

a = -24
n = 23
d = (-24 - (-4) = -20

Using these in the formula,

$\sf a_2_3\ =\ a\ +\ (n\ -\ 1)d\\\\\\a_2_3\ =\ -24\ +\ (23\ -\ 1)\ \times\ (-20)\\\\\\a_2_3\ =\ -24\ +\ 22\ \times (-20)\\\\\\a_2_3\ =\ -24\ -\ 440\\\\\\\bf a_2_3\ =\ -464$

Therefore, the 23rd term in the AP is -464.

Hope it helps. :)

7 0

2 years ago