3 years ago

How to solve the 30$+1000$????

Mathematics

1 answer:

Maksim231197 [3]3 years ago

4 0

Answer:

1030

Step-by-step explanation:

30+1000=1030

You might be interested in

Solve the inequality.

Dima020 [189]

Answer:

Step-by-step explanation:

x + 8 < - 28

x < - 28 - 8

x < - 36

Option A is the correct answer

3 0

3 years ago

What is the greatest common factor of 50, 25 and 100

Zina [86]

Answer:

The common factors for 50,25,100 50 , 25 , 100 are −25,−5,−1,1,5,25 - 25 , - 5 , - 1 , 1 , 5 , 25

3 0

3 years ago

At rolling hills middle school, the ratio of the total number of students to the number of students with pets is 3 to 1. If ther

Roman55 [17]

3/1 = 243/x
243 = 3x
81 students

5 0

3 years ago

Who want brainlist????

Natalka [10]

I want brainlist, i have 0/5

6 0

3 years ago

Read 2 more answers

A study involves a population of 400 tall women. This population has a mean height of 179.832 cm and a standard deviation of 12.

Fofino [41]

Answer: 0.0386

Step-by-step explanation:

Given: The population of 400 tall women has a mean height $(\mu)$ of 179.832 cm and a standard deviation $(\sigma)$ of 12.192 cm.

Let X be a random variable that represents the height of woman.

Sample size : n= 50

The probability that the mean for this sample group is above 182.88 will be :

$P(\overline{X}>182.88)\\\\=P(\dfrac{\overline{X}-\mu}{\dfrac{\sigma}{\sqrt{n}}}>\dfrac{182.88-179.832}{\dfrac{12.192}{\sqrt{50}}})\\\\ =P(Z>1.7678)\ \ \ [Z=\dfrac{\overline{X}-\mu}{\dfrac{\sigma}{\sqrt{n}}}]\\\\=1-P(Z$

Hence, Required probability = 0.0386

3 0

3 years ago

How to solve the 30$+1000$???? ​

How to solve the 30$+1000$????