There are an infinite number of expressions whose value is not 18.
Here are a few of them:
4π
√7
cos(any angle)
sin(any angle)
(x + 12) whenever 'x' is NOT 6
Formula for an is 3n - 11
Step-by-step explanation:
- Step 1: Equation for a(n) = a + (n - 1)d where a = - 8, d = common difference = a2 - a1 = -5 - -8 = 3
⇒ a(n) = -8 + (n - 1)3 = - 8 + 3n - 3 = 3n - 11
Answer:
a.) 70 km per hour
b.) 245 km
Step-by-step explanation:
a.) Find how far the car can travel per hour by dividing:

The car travels at a rate of 70 km per hour.
b.) Make an equation with <em>h</em> as hours and <em>d</em> as the distance the car can travel:

Insert the hours:

Simplify:

At a rate of 70 km per hour, in 3.5 hours, the car can travel a total of 245 km.
Answer:
The answer to your question is
Step-by-step explanation:
Data
f(x) = -2(x - 4)² + 2
Process
1) Assign values to x and evaluate the function to get y.
x f(x) y
0 -2(0 - 4)² + 2 -30
1 -2(1 - 4)² + 2 -16
2 -2(2 - 4)² + 2 - 6
3 -2(3 - 4)² + 2 0
4 -2(4 - 4)² + 2 2
5 -2(5 - 4)² + 2 0
6 -2(6 - 4)² + 2 -6
2.- Plot the points (see the graph below)
3.- Join the points (see the graph below)
Answer: 3.751*10^18kg
Step-by-step explanation:
δ =619.09−0.000097p....equa1 where p (the distance from the center of the earth) is measured in meters and δ is measured in kilograms per cubic meter.
Calculating the density of air at 5km above earth surface
P = 5000m + 6370000m = 6.375*10^6m
δ = 619.09 -(.000097* 6.375*10^6)
δ = 0.715kg/m^3 = density
Since Mass = density*volume...equ2
To calculate volume of air around the spherical earth at height 5km
V = (4/3 pai R^3) - (4/3pai r^3) ...equation 3 where R =6.375*10^6m, r = 6.37*10^6
Substituting R and r in equation 2 to solve for volume of air
V = 1.085*10^21 - 1.08*10^21
V = 5.25*10^18m^3
Substituting δ and V into equation 2 to solve for mass of air
M = 0.715 * (5.25*10^18)
M = 3.751*10^18kg