The length of each of two sides of a triangle is The third side's length is 15sqrt(2) . Classify the triangle

Alex applies 350 n of force to move his stalled car 40 m how much work did alex do

Katyanochek1 [597]

Step-by-step explanation:

Work done = Force × displacement

= 350 × 40

=14000J

7 0

3 years ago

Problem number 26 of the Rhind Papyrus says: Find a quantity such that when it is added to StartFraction 1 Over 4 EndFraction of

Rzqust [24]

Answer:

x=12

Step-by-step explanation:

For the given situation , a quantity x is added to $\frac{1}{4} x$ gives 15.

We can set up equation as

$x+\frac{1}{4}x=15$

Multiply each term by 4 on both sides to get rid the denominator.

It gives,

4 x+x=60

Now, combine like terms

5 x=60

Divide both sides by 5

x=12.

6 0

3 years ago

Dont get it wrong, if its wrong i fail, explain how you got your answer

damaskus [11]

Answer: 50.24

Area of a circle is pi times r^2

The r is 1/2 the d

So 8/2 = 4

Pi times 4^2= 50.24

7 0

2 years ago

Norma and Albert both clean pools. Each charges a flat fee to clean a pool. Norma cleans 12 pools in 8 hours and earns $270. Alb

Novosadov [1.4K]

Answer:

1.5 per hour : 1.2 per hour

Step-by-step explanation:

The computation of the ratio is shown below:

For norma, the one pool would be

= 12 pools ÷ 8 hours

= 1.5 per hour

And for albert, the one pool would be

= 9 pools ÷ 7.5 hours

= 1.2 per hour

So the ratio between them is

1.5 per hour : 1.2 per hour

4 0

2 years ago

According to the article "Characterizing the Severity and Risk of Drought in the Poudre River, Colorado" (J. of Water Res. Plann

mihalych1998 [28]

Answer:

(a) P (Y = 3) = 0.0844, P (Y ≤ 3) = 0.8780

(b) The probability that the length of a drought exceeds its mean value by at least one standard deviation is 0.2064.

Step-by-step explanation:

The random variable Y is defined as the number of consecutive time intervals in which the water supply remains below a critical value y₀.

The random variable Y follows a Geometric distribution with parameter p = 0.409.

The probability mass function of a Geometric distribution is:

$P(Y=y)=(1-p)^{y}p;\ y=0,12...$

(a)

Compute the probability that a drought lasts exactly 3 intervals as follows:

$P(Y=3)=(1-0.409)^{3}\times 0.409=0.0844279\approx0.0844$

Thus, the probability that a drought lasts exactly 3 intervals is 0.0844.

Compute the probability that a drought lasts at most 3 intervals as follows:

P (Y ≤ 3) = P (Y = 0) + P (Y = 1) + P (Y = 2) + P (Y = 3)

$=(1-0.409)^{0}\times 0.409+(1-0.409)^{1}\times 0.409+(1-0.409)^{2}\times 0.409\\+(1-0.409)^{3}\times 0.409\\=0.409+0.2417+0.1429+0.0844\\=0.8780$

Thus, the probability that a drought lasts at most 3 intervals is 0.8780.

(b)

Compute the mean of the random variable Y as follows:

$\mu=\frac{1-p}{p}=\frac{1-0.409}{0.409}=1.445$

Compute the standard deviation of the random variable Y as follows:

$\sigma=\sqrt{\frac{1-p}{p^{2}}}=\sqrt{\frac{1-0.409}{(0.409)^{2}}}=1.88$

The probability that the length of a drought exceeds its mean value by at least one standard deviation is:

P (Y ≥ μ + σ) = P (Y ≥ 1.445 + 1.88)

= P (Y ≥ 3.325)

= P (Y ≥ 3)

= 1 - P (Y < 3)

= 1 - P (X = 0) - P (X = 1) - P (X = 2)

$=1-[(1-0.409)^{0}\times 0.409+(1-0.409)^{1}\times 0.409\\+(1-0.409)^{2}\times 0.409]\\=1-[0.409+0.2417+0.1429]\\=0.2064$

Thus, the probability that the length of a drought exceeds its mean value by at least one standard deviation is 0.2064.

6 0

3 years ago