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slega [8]
3 years ago
6

What is the vertex of the quadratic function below y=3x^2-12x+17

Mathematics
1 answer:
RUDIKE [14]3 years ago
3 0

Answer:

(2,  5 )

Step-by-step explanation:

Given a quadratic in standard form : y = ax² + bx + c : a ≠ 0

Then the x- coordinate of the vertex is

x_{vertex} = - \frac{b}{2a}

y = 3x² - 12x + 17 ← is in standard form

with a = 3 and b = - 12, thus

x_{vertex} = - \frac{-12}{6} = 2

Substitute x = 2 into the function for corresponding value of y

y = 3(2)² - 12(2) + 17 = 12 - 24 + 17 = 5

vertex = (2, 5 )

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