The electric force between charged bodies decreases by a factor equal to the relative permittivity, ie:
F ∝ 1/ε
F = electric force, ε = relative permittivity
Find the scaling factor of F due to the change in ε:
k = 1/(0.9/0.45) = 1/2 = 0.5
Multiply the original F by k to find the new F:
F = 0.8N×k
F = 0.8N×0.5
F = 0.4N
Explanation:
Q1. Given:
v = 0 m/s
a = -5.5 m/s²
t = 3.5 s
Find: Δx
Δx = vt − ½ at²
Δx = (0 m/s) (3.5 s) − ½ (-5.5 m/s²) (3.5 s)²
Δx ≈ 33.7 m
Q2. Given:
Δx = 400 m
v₀ = 7.0 m/s
v = 35 m/s
Find: a
v² = v₀² + 2aΔx
(35 m/s)² = (7.0 m/s)² + 2a (400 m)
a = 1.47 m/s²
Answer:
ionic
ionic
covalent
covalent (i think)
Explanation:
ionic= donate electrons (gain/lose)... (results in ions that have +/- charge, are no longer neutral)
covalent= share electrons
Answer:
by taking other atoms that have one shell and putting it i the spot that they need t in
Explanation: