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3 years ago

1. Choose the statement that does not accurately describe observations

Physics

2 answers:

erastova [34]3 years ago

3 0

Answer:What are the statements?

Explanation:

telo118 [61]3 years ago

3 0

Answer:

obtuse, oblique, unaware, over stimulate, distracted, undrewhelmed...

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if the frequency of a sound wave in air remains constant, its energy can be varied by changing its what

Anastaziya [24]

Amplitude, is the answer to the question

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3 years ago

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Charges q, q, and – q are placed on the x-axis at x = 0, x = 4 m, and x = 6 m, respectively. At which of the following points do

MrRissso [65]

Answer:

can you show a graph but if not i believe the answer is x=6m

Explanation:

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3 years ago

Name an element in the same period as rubidium

Artyom0805 [142]

Answer: Potassium(K)

Explanation:

its an alkali metal placed under sodium and its over rubidium, its also the first element of period 4

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2 years ago

The Steamboat Geyser in Yellowstone National Park shoots water into the air at 48.0 m/s. How

qwelly [4]

Answer:

The maximum height reached by the water is 117.55 m.

Explanation:

Given;

initial velocity of the water, u = 48 m/s

at maximum height the final velocity will be zero, v = 0

the water is going upwards, i.e in the negative direction of gravity, g = -9.8 m/s².

The maximum height reached by the water is calculated as follows;

v² = u² + 2gh

where;

h is the maximum height reached by the water

0 = u² + 2gh

0 = (48)² + ( 2 x -9.8 x h)

0 = 2304 - 19.6h

19.6h = 2304

h = 2304 / 19.6

h = 117.55 m

Therefore, the maximum height reached by the water is 117.55 m.

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3 years ago

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Two metra trains approach each other on separate but parallel tracks. one has a speed of 90 km/hr, the other 80 km/hr. initially

Gennadij [26K]

The trains take <u>57.4 s</u> to pass each other.

Two trains A and B move towards each other. Let A move along the positive x axis and B along the negative x axis.

therefore,

$v_A=90 km/h\\ v_B=-80 km/h$

The relative velocity of the train A with respect to B is given by,

$v_A_B=v_A-v_B\\ =(90km/h)-(-80km/h)\\ =170km/h$

If the train B is assumed to be at rest, the train A would appear to move towards it with a speed of 170 km/h.

The trains are a distance d = 2.71 km apart.

Since speed is the distance traveled per unit time, the time taken by the trains to cross each other is given by,

$t= \frac{d}{v_A_B}$

Substitute 2.71 km for d and 170 km/h for $v_A_B$

$t= \frac{d}{v_A_B}\\ =\frac{2.71 km}{170 km/h} \\ =0.01594 h$

Express the time in seconds.

$t=(0.01594h)(3600s/h)=57.39s$

Thus, the trains cross each other in <u>57.4 s</u>.

6 0

3 years ago