Answer:
A) E = 0N/C
B) 0i + 0^^j
C) F = 0N
D) 0^i + 0^j
Explanation:
You assume that the rings are in the zy plane but in different positions.
Furthermore, you can consider that the origin of coordinates is at the midway between the rings.
A) In order to calculate the magnitude of the electric field at the middle of the rings, you take into account that the electric field produced by each ring at the origin is opposite to each other and parallel to the x axis.
You use the following formula for the electric field produced by a charge ring at a perpendicular distance of r:
(1)
k: Coulomb's constant = 8.98*10^9Nm^2/C
Q: charge of the ring
r: perpendicular distance to the center of the ring
R: radius of the ring
You use the equation (1) to calculate the net electric field at the midpoint between the rings:
The electric field produced by each ring has the same magnitude but opposite direction, then, the net electric field is zero.
B) The direction of the electric field is 0^i + 0^j
C) The magnitude of the force on a proton at the midpoint between the rings is:
D) The direction of the force is 0^i + 0^j
Explanation:
The same thing happened in pressure cooker but the temperature inside is most higher.
hope you like my answer
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The car's speed was zero at the beginning of the 12 seconds,
and 18 m/s at the end of it. Since the acceleration was 'uniform'
during that time, the car's average speed was (1/2)(0 + 18) = 9 m/s.
12 seconds at an average speed of 9 m/s ==> (12 x 9) = 108 meters .
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That's the way I like to brain it out. If you prefer to use the formula,
the first problem you run into is: You need to remember the formula !
The formula is D = 1/2 a T²
Distance = (1/2 acceleration) x (time in seconds)²
Acceleration = (change in speed) / (time for the change)
= (18 m/s) / (12 sec)
= 1.5 m/s² .
Distance = (1/2 x 1.5 m/s²) x (12 sec)²
= (0.75 m/s²) x (144 sec²) = 108 meters .
Answer:
p= 400.29N
........the horizontal force
Explanation:
Given data
mass=25 kg
small cube mass mass=4 kg
Us (The Coefficient of static b/w two cubes) = 0.71
to find
The horizontal force to keep the small cube from sliding downward
Solution
F=ma.........................from Newton Second law
Where F=force
a=acceleration
m=mass
we can write equation in form of acceleration
a=F/m
The acceleration on small box is same as that on the large box.
Let P be force to find.
then:
a=p/(25kg+4kg)
a=p/(29kg)m/s²
The force acting on small box:
F=ma
f=4*(p/29)N........................normal force
friction force= Us*(normal force).........where Us is coefficient of static friction.
friction force= 0.71*(4*p/29)
Now to find weight
weight= mg
weight= 4*9.8
for the object(small box) not to slide down the friction force b/w the two objects have to be exactly the same as the weight of the object.
0.71*(4*p/29)=4*9.8
solving for p(force)
p= 400.29N
........the horizontal force
