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Licemer1 [7]
3 years ago
12

What is the square root of 41

Mathematics
2 answers:
Molodets [167]3 years ago
8 0
6.043124 is the answer
Olin [163]3 years ago
3 0

Answer:

6.40312423743

Step-by-step explanation:

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Expand the following (4/5d - 7e)2
tensa zangetsu [6.8K]

Answer: \dfrac{16d^2}{25}+49e^2-\dfrac{56de}{5}

Step-by-step explanation:

Given

The expression is

(\dfrac{4d}{5}-7e)^2

Use identity (a-b)^2=a^2+b^2-2ab

Apply identity

\Rightarrow \left( \dfrac{4d}{5}-7e\right)^2=\left( \dfrac{4d}{5}\right)^2+(7e)^2-2\times \left( \dfrac{4d}{5}\right)(7e)\\\\\Rightarrow \left( \dfrac{4d}{5}-7e\right)^2=\dfrac{16d^2}{25}+49e^2-\dfrac{56de}{5}

4 0
3 years ago
Find the measure of the indicated arcs or central angles in OA. DG is a diameter.
lara31 [8.8K]

Answer:

Arc DE = 90°

m<GAB = 82°

Arc DC = 49°

Step-by-step explanation:

Given:

m<EAF = 74°

m<EAD = right angle = 90°

Arc BG = 82°

Required:

Arc DE,

<GAB, and

Arc DC

Solution:

Recall that the central angle measure = the intercepted arc measure.

Therefore:

✔️Arc DE = m<EAD

Arc DE = 90° (Substitution)

✔️m<GAB = arc BG

m<GAB = 82° (Substitution)

✔️Arc DC = m<CAD

Find m<CAD

m<CAD = ½(180 - m<GAB)

m<CAD = ½(180 - 82)

m<CAD = 49°

Arc DC = m<CAD

Arc DC = 49°

6 0
3 years ago
Please help me! thanks in advance trying to raise my grade
Igoryamba

Answer:

x=53

Step-by-step explanation:

In the attachment, it shows how the angle 53 is vertically opposite to the one in blue. Which happens to be corresponding, therefore equal, to the angle x.

Have a nice day!!! :-)

<u>KA</u>

3 0
3 years ago
Read 2 more answers
If the area of the circle below is 18 ft2, what is the area of the shaded sector?
LuckyWell [14K]

Answer:

It would be C

Step-by-step explanation:

since the whole area of the circle is 18 and the sector takes up one-fourth of the circle you would just divide 18 by 4 to get 4.5

5 0
4 years ago
Read 2 more answers
Which is not an equation of the line that passes through the points (1, 1) and (5, 5)?
maria [59]

(1,\ 1)\to x_1=1,\ y_1=1\to x_1=y_1\\\\(5,\ 5)\to x_2=5,\ y_2=5\to x_2=y_2\\\\\text{Therefore we have the equation}\ y=x\\\\\text{subtract y from both sides}\\\\\boxed{x-y=0\to\boxed{B}}\to\boxed{y-x=0\to\boxed{A.}}\\\\Answer:\ C.\ -x-y=0

8 0
3 years ago
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