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GaryK [48]
3 years ago
7

Quadrilateral PQRS is shown

Mathematics
1 answer:
aniked [119]3 years ago
8 0

Answer:

m∠QPS = 59

Step-by-step explanation:

59 + (7x-5) = 180

x = 18

If you substitute 59 with the other answer options you will get a decimal.

I hope that this could help!!!!

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Diana is working on a painting for school. She needs 1 1/5 ounces of yellow paint and 2 1/2 ounces of orange paint. How much les
Eduardwww [97]

Answer:

1 3/10

Step-by-step explanation:

We are to determine the difference the paint of yellow and orange paint

The equation we are to solve is

2\frac{1}{2}  - 1\frac{1}{5}

The equation can be solved by taking the following steps

  1. Subtract the two whole numbers
  2. divide each denominator by the least common multiple of the denominator and multiply the figures by the numerator

1\frac{5 - 2}{10} = 1\frac{3}{10}

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3 years ago
Which equation represents a proportional relationship that has a constant of proportionality equal to -10?
harkovskaia [24]

Answer:the answer isn’t on edginuity

Step-by-step explanation:

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F ∠A is 95° and ∠B is 105°, what is ∠C?<br> A) 75° <br> B) 85° <br> C) 95° <br> D) 105°
Jobisdone [24]

The question is missing important data. The quadrilateral having vertices A, B, C and D is a cyclic quadrilateral.

Answer:

B) 85°

Step-by-step explanation:

Given:

A cyclic quadrilateral with ∠A is 95° and ∠B is 105°.

For a cyclic quadrilateral, the sum of the opposite interior angles is equal to 180°

Therefore, sum of angles A and C is 180°.

\angle A + \angle C=180\°\\95\°+\angle C=180\°\\\angle C=180-95\\\angle C =85\°

Therefore, the correct option is option B) 85°

6 0
4 years ago
Read 2 more answers
The ratio of boys to girls in the ninth grade is 7 to 9. there are 218 girls set up a proportion to model this information
pentagon [3]

Answer:

24.2

Step-by-step explanation:

7 0
3 years ago
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Find the square roots by division method of 210,681 please tell me
padilas [110]

Answer:

  459

Step-by-step explanation:

The "long division method" algorithm for square root makes use of the relation described by the square of a binomial.

  (a +b)² = a² +2ab +b² = a² +b(2a +b)

<h3>Steps</h3>

The value for which the root is desired is written with digits marked off in pairs either side of the decimal point.

The initial digit of the root is the integer part of the square root of the most-significant pair. Here that is floor(√21) = 4. This is shown in the "quotient" spot above the leftmost pair. The square of this value is subtracted, and the next pair brought down for consideration. Here, that means the next "dividend" is 506.

The next "divisor" will be 2 times the "quotient" so far, with space left for a least-significant digit. Here, that means 506 will be divided by 80 + some digits. As in regular long division, determining the missing digit involves a certain amount of "guess and check." We find that the greatest value 'b' that will give b(80+b) ≤ 506 is b=5. This is the next "quotient" digit and is placed above the "dividend" pair 06. The product 5(85) = 425 is subtracted from 506, and the next "dividend" pair is appended to the result. This makes the next "dividend" equal to 8181.

As in the previous step, the next "divisor is 2 times the quotient so far: 2×45 = 90, with space left for the least significant digit. 8181 will be divided by 900-something with a "quotient" of 9. So, we subtract the product 9(909) = 8181 from the "dividend" 8181 to get the next "dividend." That result is zero, so we're finished.

The root found here is 459.

__

<em>Additional comment</em>

In practice, roots are often computed using iterative methods, with some function providing a "starter value" for the iteration. Some iterative methods can nearly double the number of good significant digits in the root at each iteration.

Using this "long division method," each "iteration" adds a single significant digit to the root. Its advantage is that it always works, and is generally suitable for finding roots by hand. Once the number of root digits begins to get large, the "divisor" starts to be unwieldy.

8 0
2 years ago
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