Quadrilateral PQRS is shown

Mathematics

1 answer:

aniked [119]3 years ago

8 0

Answer:

m∠QPS = 59

Step-by-step explanation:

59 + (7x-5) = 180

x = 18

If you substitute 59 with the other answer options you will get a decimal.

I hope that this could help!!!!

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Anyone help me ASAP, its due in an hour, plz show all the working, THANK YOU SO MUCH

Leona [35]

Answer:

Step-by-step explanation:

First, start out with the parent function:

$y = b^{x}$

Now, we look at the transformations, and make the equation.

We see that the graph <u>shifted down 4 units</u>, since the <u>graph's horizontal asymptote</u> is at y = -4.

$y = b^{x} - 4$

We see point (0, -3) to point (1, -1). The value of b would be 3. The reason is that when you <u>plug 0 in, you get 1, then 1 - 4 equals 3. (0, -3),</u>

<u>Then, when you plug in 1, you get 3, then 3 - 4 equals -1. This matches up with the graph.</u>

<u />

This is the answer:

$y = 3^{x}-4$

#teamtrees #WAP (Water And Plant)

8 0

3 years ago

X^2 + 32x + 256 = 1<br>please show steps

Elena L [17]

$\boxed{x_{1}=-15} \\ \\ \boxed{x_{2}=-17}$

<h2>Explanation:</h2>

In this case, we have the following equation:

$x^2+32x+256=1$

But we can write this equation as:

$x^2+32x+256=1 \\ \\ Subtract \ -1 \ from\ both \ sides: \\ \\ x^2+32x+256-1=1-1 \\ \\ x^2+32x+255=0$

So this final result is a quadratic equation written in Standard Form ( $ax^2+bx+c=0$ ). We need to find the solutions to this equations, so let's use quadratic formula:

$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ a=1 \\ b=32 \\ c=255 \\ \\ \\ x=\frac{-32 \pm \sqrt{(32)^2-4(1)(255)}}{2(1)} \\ \\ x=\frac{-32 \pm \sqrt{1024-1020}}{2} \\ \\ x=\frac{-32 \pm \sqrt{4}}{2} \\ \\ x=\frac{-32 \pm 2}{2} \\ \\ Finally, \ two \ solutions: \\ \\ \boxed{x_{1}=-15} \\ \\ \boxed{x_{2}=-17}$