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Step2247 [10]
3 years ago
7

If nobody answers this they think im hot

Mathematics
1 answer:
cupoosta [38]3 years ago
5 0

NO YOU ARE NOT

AND THANK YOU

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A representative from the National Football League's Marketing Division randomly selects people on a random street in Kansas Cit
Orlov [11]

Using the binomial distribution, we have that:

a) 0.1024 = 10.24% probability that the marketing representative must select 4 people to find one who attended the last home football game.

b) 0.2621 = 26.21% probability that the marketing representative must select more than 6 people to find one who attended the last home football game.

c) The expected number of people is 4, with a variance of 20.

For each person, there are only two possible outcomes. Either they attended a game, or they did not. The probability of a person attending a game is independent of any other person, which means that the binomial distribution is used.

Binomial probability distribution  

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}  

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • p is the probability of a success on a single trial.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

The expected number of <u>trials before q successes</u> is given by:

E = \frac{q(1-p)}{p}

The variance is:

V = \frac{q(1-p)}{p^2}

In this problem, 0.2 probability of a finding a person who attended the last football game, thus p = 0.2.

Item a:

  • None of the first three attended, which is P(X = 0) when n = 3.
  • Fourth attended, with 0.2 probability.

Thus:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{3,0}.(0.2)^{0}.(0.8)^{3} = 0.512

0.2(0.512) = 0.1024

0.1024 = 10.24% probability that the marketing representative must select 4 people to find one who attended the last home football game.

Item b:

This is the probability that none of the first six went, which is P(X = 0) when n = 6.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{6,0}.(0.2)^{0}.(0.8)^{6} = 0.2621

0.2621 = 26.21% probability that the marketing representative must select more than 6 people to find one who attended the last home football game.

Item c:

  • One person, thus q = 1.

The expected value is:

E = \frac{q(1-p)}{p} = \frac{0.8}{0.2} = 4

The variance is:

V = \frac{0.8}{0.04} = 20

The expected number of people is 4, with a variance of 20.

A similar problem is given at brainly.com/question/24756209

3 0
2 years ago
1. What is the surface area of the cube
Marrrta [24]

Answer:

96 in. squared

Step-by-step explanation:

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3 years ago
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Simplify 12 to the 16th power over 12 to the 4th power. 1212 124 112 14
Law Incorporation [45]

Greetings from Brasil...

<em />

Here's our problem:

\large{\frac{12^{16}}{12^{4}}}

From potentiation properties:

Mᵃ ÷ Mᵇ = Mᵃ⁻ᵇ

<em>division of power of the same base: I repeat the base and subtract the exponents</em>

<em />

Bringing to our problem

12¹⁶ ÷ 12⁴

12¹⁶⁻⁴

<h2>12¹²</h2>

4 0
3 years ago
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A force of F = 1.12×104 Newtons does work of W = 1.18×106 Joules. What is the approximate displacement in meters (Displacement =
alexira [117]

Answer: 105.3 m

Step-by-step explanation:

Given

Applied force is F=1.12\times 10^4\ N

Work done is W=1.18\times 10^6\ J

Work done is given by the displacement done by the force.

\Rightarrow W=F\cdot s\\\Rightarrow 1.18\times 10^6=1.12\times 10^4\cdot s\\\\\Rightarrow s=1.05\times 10^2\\\Rightarrow s=105.3\ m

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3 years ago
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Help I'm taking a test, thx!
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The answer is 4

how to show the work on here or how to send a picture of my notes :)
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