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3 years ago

I'll mark you the brainiest if you get this right thx x

Mathematics

1 answer:

GenaCL600 [577]3 years ago

6 0

A) triangle c, has the largest area
b) a= 1/2 (3) (3) a= 4.5
the picture shows what i mean hope this helps :)

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A company has two manufacturing plants with daily production levels of 5x+14 items and 3x−7 items, respectively. The first plan

Anastasy [175]

Answer:

3x+24 more widgets

Step-by-step explanation:

A company owns two manufacturing plants:

1st plant: 8x+17 widgets;2nd plant: 5x-7 widgets.

To find how many more items the first plant produces daily than the second plant, we have to subtract from the number of widgets the first plant produces the second plant produces. So,

(8x+17)-(5x-7)\\ \\=8x+17-5x+7\ [\text{Eliminate brackets}]\\ \\=(8x-5x)+(17+7)\ [\text{Combine the like terms}]\\ \\=3x+24

hope this helps!

Step-by-step explanation:

4 0

3 years ago

Please answer this correctly

r-ruslan [8.4K]

Answer:

40 - 59 ⇒ 6

60 - 79 ⇒ 5

3 0

3 years ago

Read 2 more answers

The mean annual income for adult women in one city is $28,520 and the standard deviation of the incomes is $5600. The distributi

pshichka [43]

Answer:

$E(\bar{x}) = 28520$

Standard error of mean = 689

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = $28,520

Standard Deviation, σ = $5600

Mean of sampling distribution =

$E(\bar{x}) = \mu = 28520$

As per Central Limit Theorem, if the sample size is large enough, then the sampling distribution of the sample means follow approximately a normal distribution.

Sample size, n = 66

Since the sample size is large, we can use normal distribution for approximation.

Standard error of mean =

$\displaystyle\frac{\sigma}{\sqrt{n}} = \frac{5600}{\sqrt{66}} = 689.31 \approx 689$

7 0

3 years ago

What angle is is letter C?

stiv31 [10]

Answer:

The angle measure for angle c is 138 degrees

8 0

4 years ago

Read 2 more answers

Rewrite sin^4xtan^2x in terms of the first power of the cosine

Vikki [24]

$\sin ^4 x \tan ^2 x = \dfrac{\sin ^4 x\ \sin ^2 x }{\cos ^2 x} = \dfrac{\sin^6 x}{\cos ^2 x} = \dfrac{(\sin ^2 x)^3}{\cos^2 x}=\dfrac{(1-\cos^2 x)^3}{\cos^2 x}$

7 0

3 years ago