Answer:
Since you did not provide any other information, I did some research and might have found the original question/ answer choices. If this is the correct question, then your answer should be D.)
It would be the first answer. Bubble. I don't know what you call it. But yeah, it's the first one.
Answer:
The vertex for the function f(x) = 3(x – 2)2 + 4 is at (2, 4).
Step-by-step explanation:
Find the vertex for f(x) = 3 (x - 2)^2 + 4
f(x) = 3 (x - 2)^2 + 4 can also be written as:
y = 3 (x - 2)^2 + 4
To find critical points, first compute f'(x):
d/(dx)(3 (x - 2)^2 + 4) = 6 (x - 2):
f'(x) = 6 (x - 2)
Solve 6 (x - 2) = 0
6x - 12 = 0
6x = 12
x = 2
iI you substitute x = 2 in 3 (x - 2)^2 + 4 then you get:
y = 3 (x - 2)^2 + 4
x = 2
y = 3 (2 - 2)^2 + 4
y = 3 (0)^2 + 4
y = 3 (0) + 4
y = 4
Answer: The vertex for the function f(x) = 3(x – 2)2 + 4 is at ( 2, 4 ).
If the gradient is the same the line will be parallel. Your answer is <span>Y=2x + 3 </span>
You do parenthesis first following the rules of PEMDAS. so 2-1=1. so now you solve 4^2 which is 16. then you go over to 10 divided by 5 which is 2. which simplifies the equation down to 16+1x2. so you do 1x2 which is 2 then add 16. your final answer is 18 (:
