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baherus [9]
3 years ago
6

Write three consecutive multiples of 13 in a general form.

Mathematics
1 answer:
S_A_V [24]3 years ago
5 0

Answer:

answer given in step by step...

Step-by-step explanation:

13x+13(x+1)+13(x+2)=312

13x+13x+13+13x+26=312

39x+39=312

39x=312-39

39x=273

x=7

first number=13x=13*7=91

second number=13(8)=104

third number=13(9)=117

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Determine whether the series is convergent or divergent. 1 2 3 4 1 8 3 16 1 32 3 64 convergent divergent Correct:
Vanyuwa [196]

Answer:

This series diverges.

Step-by-step explanation:

In order for the series to converge, i.e. \lim_{n \to \infty} a_n =A it must hold that for any small \epsilon>0, there must exist n_0\in \mathbb{N} so that starting from that term of the series all of the following terms satisfy that  |a_n-A|n_0 .

It is obvious that this cannot hold in our case because we have three sub-series of this observed series. One of them is a constant series with a_n=1 , the other is constant with a_n=3 , and the third one has terms that are approaching infinity.

Really, we can write this series like this:

a_n=\begin{cases} 1 \ , \ n=4k+1, k\in \mathbb{N}_0\\ 2^{k}\ , \ n=2k, k\in \mathbb{N}_0\\3\ , \ n=4k+3, k\in \mathbb{N}_0\end{cases}

If we  denote the first series as b_n=1, we will have that \lim_{k \to \infty} b_k=1.

The second series is denoted as c_k=2^k and we have that \lim_{k \to \infty} c_k=+\infty.

The third sub-series d_k=3 is a constant series and it holds that \lim_{k \to \infty} d_k=3.

Since those limits of sub-series are different, we can never find such n_0\\ so that every next term of the entire series is close to one number.

To make an example, if we observe the first sub-series if follows that A must be equal to 1. But if we chose \epsilon =1, all those terms associated with the third sub-series will be out of this interval (A-1, A+1)=(0, 2).

Therefore, the observed series diverges.

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4 years ago
What time is 17 hours after 1:00 p.m?
lana66690 [7]

Answer:

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Step-by-step explanation:

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4 years ago
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For #2, the best graph would be a bar graph because you will easily be able to see the comparison between the prices in the bars.  You will be able to easily see approximate differences and how many times greater or smaller.

For #3, a histogram will best display this data because there will be many scores from a football season to represent, and a histogram organizes a lot of data into intervals while still allowing us to see tendencies in the bars.
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4 years ago
SOS *Algebra one*
user100 [1]
This can be done in two ways
One method is to check the answer options in both f(x) and g(x) and select the one that matches for both.
The second is to form a quadratic equation and solving as such:
f(x) = g(x)
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(x - 4)(x + 1) = 0
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