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baherus [9]
3 years ago
6

Write three consecutive multiples of 13 in a general form.

Mathematics
1 answer:
S_A_V [24]3 years ago
5 0

Answer:

answer given in step by step...

Step-by-step explanation:

13x+13(x+1)+13(x+2)=312

13x+13x+13+13x+26=312

39x+39=312

39x=312-39

39x=273

x=7

first number=13x=13*7=91

second number=13(8)=104

third number=13(9)=117

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400 passengers

Step-by-step explanation:

To solve the problem, a proportion would be best!

First, let's set up the left side of the proportion. Percents, when used in parts, are always part of 100%, making 100% a whole. We'll use both 10% and 100% as our first fraction, which should look something like this:

\frac{10p}{100w} (with <em>p </em>standing for <em>part </em>and <em>w</em> standing for the <em>whole</em>)

Next, let's set up the right side of our proportion. We'll use the 40 for our part and x for our whole since that is the number we are solving for. The proportion should now look like this:

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To solve, just cross multiply and divide! Multiply 40 by 100 to give you 4,000. Next, divide 4,000 by the remaining 10 to give you a final answer of 400. If 40 passengers on the flight are in first class, then there are 400 total passengers. Hope this helps!

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