1. Take an arbitrary point that lies on the first line y=3x+10. Let x=0, then y=10 and point has coordinates (0,10).
2. Use formula
to find the distance from point
to the line Ax+By+C=0.
The second line has equation y=3x-20, that is 3x-y-20=0. By the previous formula the distance from the point (0,10) to the line 3x-y-20=0 is:
.
3. Since lines y=3x+10 and y=3x-20 are parallel, then the distance between these lines are the same as the distance from an arbitrary point from the first line to the second line.
Answer:
.
Answer:
-2
Step-by-step explanation:
7x-21-10x+20=5
7x-10x-1=5
-3x=5+1
x=-6/3
x=-2
Postulate1:A line contains atleast 2 points.Postulate1a:A plane contains at least 3 points not all on one line.Postulate1b:Space contains atleast four points not all on one plane